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Sever21 [200]
3 years ago
11

The owner of a hot dog stand receives a loan of $3,750 at 8.25% for 9 months. find the amount of simple interest.(round to the n

earest cent)
Mathematics
1 answer:
Ivan3 years ago
7 0
Hello! The formula for simple interest is prt. That means you multiply the principal (initial amount) by the rate (simple interest percentage), by the amount of time (could be in months or years). So, the loan is $3,750 and the rate is 8.25% for 9 months. 9 months is 3/4 of the year, because there are 12 months in 1 year and 9/12 is 0.75. Let's multiply. 3,750 * 8.25% (0.0825) is 309.375 Now, multiply that number by 0.75 to get 232.03125 or 232.03 when rounded to the nearest hundredth (cent). The amount of simple interest is $232.03.
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(-2, 8) and (1,2)<br> slope
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Answer:

X=6

Y= -1

Step-by-step explanation:

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3 years ago
in training for a race, each day aylin ran 1.5% further than the day before. if on the 27th day of training she ran approx 6 mil
Kazeer [188]

Answer: 5%

Step-by-step explanation:

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3 years ago
A metalworker has a metal alloy that is 20​% copper and another alloy that is 60​% copper. How many kilograms of each alloy shou
puteri [66]
<h3>Answer:</h3>
  • <u>20</u> kg of 20%
  • <u>80</u> kg of 60%
<h3>Step-by-step explanation:</h3>

I like to use a little X diagram to work mixture problems like this. The constituent concentrations are on the left; the desired mix is in the middle, and the right legs of the X show the differences along the diagonal. These are the ratio numbers for the constituents. Reducing the ratio 32:8 gives 4:1, which totals 5 "ratio units". We need a total of 100 kg of alloy, so each "ratio unit" stands for 100 kg/5 = 20 kg of constituent.

That is, we need 80 kg of 60% alloy and 20 kg of 20% alloy for the product.

_____

<em>Using an equation</em>

If you want to write an equation for the amount of contributing alloy, it works best to let a variable represent the quantity of the highest-concentration contributor, the 60% alloy. Using x for the quantity of that (in kg), the amount of copper in the final alloy is ...

... 0.60x + 0.20(100 -x) = 0.52·100

... 0.40x = 32 . . . . . . . . . . .collect terms, subtract 20

... x = 32/0.40 = 80 . . . . . kg of 60% alloy

... (100 -80) = 20 . . . . . . . .kg of 20% alloy

6 0
3 years ago
Help pls!! this is a presentation I’m doing in class and I NEED this completed rn, ASAP!!! . What I need is just the answers for
snow_lady [41]

15. 70° because a right angle is 90° and we have the angle of ADB which is 20°. So 90°-20°=70°.

16. 70° because angle PSQ is 60° and angle QSR is 10°. So 60°+10°=70°.

17. 55° because it says it in the explanation. I assume this is a typo and they meant to ask the measurement of ADC and in that case it would be 130° because angle ADB is 75° and angle BDC is 55°. 75°+55°=130°.

18. 40° because angle PSQ is a right angle which means it's 90°. So 130°-90°=40°.

19. 140° because angle ADB is 120° and angle BDC is 20° so 120°+20°=140°.

20. 125° because again it's in the explanation. But if it's a typo and they meant what is the measurement of PSQ then it is 50° because PSR is 125° and QSR is 75° so 125°-75°=50°.

Hope this helps! :)

5 0
3 years ago
Make x the subject<br>thank you​
Leya [2.2K]

Answer:

x =\sqrt{\frac{a^6m}{b^2}+n}

General Formulas and Concepts:

  • Order of Operations: BPEMDAS
  • Equality Properties
  • Exponent Power Rule: (b^m)^n=b^{mn}

Step-by-step explanation:

<u>Step 1: Define equation</u>

a\sqrt{\frac{x^2-n}{m} } =\frac{a^2}{b}

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Multiply <em>a</em> on both sides:                    \sqrt{\frac{x^2-n}{m} } =\frac{a^3}{b}
  2. Square both sides:                              \frac{x^2-n}{m} =(\frac{a^3}{b})^2
  3. Simplify:                                               \frac{x^2-n}{m} =\frac{a^6}{b^2}
  4. Multiply <em>m</em> on both sides:                   x^2-n =\frac{a^6}{b^2}m
  5. Add <em>n</em> to both sides:                           x^2 =\frac{a^6}{b^2}m+n
  6. Simplify:                                               x^2 =\frac{a^6m}{b^2}+n
  7. Square root both sides:                      x =\sqrt{\frac{a^6m}{b^2}+n}
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2 years ago
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