All categories

4 years ago

Pls helpppp !!!! Giving 12 points for answer

Mathematics

2 answers:

mel-nik [20]4 years ago

4 0

Answer:

b. 15 x 20

Step-by-step explanation:

Alik [6]4 years ago

3 0

Hi I believe the answer is B!!!!!!

You might be interested in

Solve the problem. The half-life of plutonium-234 is 9 hours. If 50 milligrams is present now, how much will be present in 6 day

MaRussiya [10]

Answer:

4) 0.001

Step-by-step explanation:

The amount (a) present in h hours is ...

a(h) = (initial value)×(1/2)^(h/(half-life))

6 days is 6×24 hours, so the amount remaining is ...

a(6×24) = 50×(1/2)^(6×24/9) = 50/2^16 ≈ 0.001 . . . . milligrams

3 0

3 years ago

Milie mode 20 cookies for her class's porty, 8 of the

nadezda [96]

Answer:

40%

Step-by-step explanation:

It is 40% because 8/20 times 5 is 40/100 and that is 40%.

8 0

3 years ago

Y is 1 less than 2 times X which order pair fits this rule

Anni [7]

Answer:

y < 2X - 1

y = 2X - 1

Step-by-step explanation:

Let's try to make an equation from the worded problem.

"is Less than " means <

2 times means 2 * X

= 2X

y < 2X - 1

y = 2X - 1

3 0

4 years ago

You are running an experiment in class where you draw colored marbles out of a bag. There are

MaRussiya [10]

Answer:

32768 ways

Step-by-step explanation:

Given

Marbles = 8 marbles

Selection = 5 (with replacement)

Required

Determine the number of ways

Because it is a selection with replacement; each selection is as follows:

$First = 8\ marbles$

$Second = 8\ marbles$

$Third= 8\ marbles$

$Fourth = 8\ marbles$

$Fifth = 8\ marbles$

Total number of ways is then calculated as:

$Total = 8 * 8 * 8 * 8 * 8$

$Total = 32768$

5 0

3 years ago

How did he get this 1/2i ? I dont remember studying this definition in calc 1 neither calc 2!

Hitman42 [59]

The $i$ in the denominator is missing in the second expression. It should be

$\sin at=\dfrac{e^{iat}-e^{-iat}}{2i}$

This follows from

$e^{iat}=\cos at+i\sin at$
$e^{-iat}=\cos at-i\sin at$
$\implies e^{iat}-e^{-iat}=2i\sin at$
$\implies \sin at=\dfrac{e^{iat}-e^{-iat}}{2i}$

8 0

4 years ago