Answer: Let you organize and summarize your data.
Explanation: Data grouping is referred as the making a collection or cluster of data in a report .The group is made for the summarization of the information and makes easily understandable according to the subject or field due to the proper organization.
Other given options are incorrect because it does not provide the total of the report content,attractive form of the data or editing function in report.Thus the correct option is summarizing and organizing the data.
Answer:
The number of invoices for each vendor that have a larger balance due than the average balance due for all invoices.
Explanation:
This part of the code below
WHERE InvoiceTotal - PaymentTotal - CreditTotal >
(SELECT AVG (InvoiceTotal - PaymentTotal- CreditTotal)
FROM Invoices)
gives the condition to pick the invoices with balance that are greater than the average balance for all invoice.
This part of the code below
GROUP BY VendorName
ORDER BY BalanceDue DESC;
then enables the program to group the result of the above condition by VendorName and sort the resulting rows in the order of BalanceDue. You will therefore, obtain for each row in the NumberOfInvoices column, the number of invoices for each vendor that have a larger balance due than the average balance due for all invoices.
think about what she wants to do with her life and what collage is best fit for that
<span>Promoting a shape within a smart art graphic means moving it to a higher level.</span>
In your "count spaces method" before the for loop, you want to declare an int variable (let's call it spc)
then, each time you find that charat, spc++.
also, the string must be declared in the main method, not the spaces count method.
The actual code:
public class CountSpaces{
public static void main(String[] args){
String instring = "(your quote here)";
int spaces = calculateSpaces(instring);
System.out.println("The number of spaces is " + spaces);
}
public static int calculateSpaces(String in){
int spc = 0;
for(int i= 0; i<in.length; i++){
if(in.charAt(i)== ' '){
spc++;
}
}
return spc;
}
}
that should be it. If you have any questions, feel free to reach out.