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rjkz [21]
3 years ago
5

Amanda and Ndiba are selling flower bulbs for a school fundraiser. Customers can buy packages of tulip bulbs and bags of daffodi

l bulbs. Amanda sold 6 packages of tulip bulbs and 12 bags of daffodil bulbs for a total of $198. Ndiba sold 7 packages of tulip bulbs and 6 bags of daffodil bulbs for a total of $127. Find the cost each of one package of tulips bulbs and one bag of daffodil bulbs.
Mathematics
1 answer:
Mumz [18]3 years ago
7 0

Answer:

daffodil = $13 Tulip = $7

Step-by-step explanation:

6t + 12d = 198

7t + 6d = 127

6t = 198 - 12d

t = 33 -2d

substitute

7(33-2d) + 6d = 127

231 -14d +6d = 127

- 8d = -104

d =13

6t + 12(13) = 198

6t +156 = 198

6t = 42

t = 7

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Answer:

First choice

Step-by-step explanation:

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Example of, (x-1)/(x-1) has a a discontinuity at x=1 and it's removable because the fraction reduces to 1 which doesn't have a discontinuity at x=1.

Example not of, (x-1)/(x-2) has a discontinuity at x=2 and it is not removable because we can't get rid of the x-2 factor in the denominator.

The first choice has a discontinuity at x=-1 and it is removable because x^2-x-2=(x-2)(x+1) and the x+1's will cancel on top and bottom making the point at x=-1 a removable discontinuity.

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Vesnalui [34]

Answer:

Option B. x=-\frac{9}{28}(+/-)\frac{\sqrt{479}}{28}i

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

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substitute

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