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marusya05 [52]
3 years ago
13

What is 936,292 rounded to the nearest hundred thousand

Mathematics
1 answer:
Romashka [77]3 years ago
3 0
The answer is 900,000?
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What is the slope of the line that passes through (-6,1) and (2,5)?
kow [346]
Slope is simply rise/run.
or
(vertical shift)/(horizontal shift)
therefore, the x value went from -6 to 2 which means it vertically shifted by 8.
and the y value went from 1 to 5, which means it horizontally shifted by 4.
the slope is 8/4.
or 2.
8 0
3 years ago
Read 2 more answers
What is cotangent of A divided by Tangent of A?
grin007 [14]
tan A =  \frac{1}{cot A} cot A =  \frac{1}{tan A} 

\frac{1}{cot A} / \frac{1}{tanA} =1

4 0
3 years ago
The midpoint of a circle is (3,2), the
Marysya12 [62]

yo sup??

mid point of circle=centre of circle

let centre be O(3,2)

and the point be P(-4,8) and the other point be Q(x,y)

by mid point formula

-4+x/2=3 and 8+y/2=2

x=10 and y=-4

therefore coordinates of the other point are (10,-4)

Hope this helps.

3 0
3 years ago
Bethanine left at 3:00 in the afternoon and walked 3/10 of a mile to Bridget's house. Laney walked 36/100 of a mile to Bridget's
jarptica [38.1K]

Answer:

Bethanie and Laney walked a total of = 0.66 miles or (\frac{33}{50}th of a mile)

Step-by-step explanation:

Bethanie walked 3/10th of a mile

Laney walked 36/100th of a mile

Lets divide and convert them to decimal:

3 divided by 10 gives us 0.30

36 divided by 100 gives 0.36

Total they walked:

0.30 + 0.36 = 0.66 miles

That would be (in fraction):

66/100 = 33/50 of a mile

8 0
3 years ago
A perpendicular bisector, , is drawn through point C on .
Liula [17]

Answer:

The x-intercept of CD is B(18/5,0). The point C(32,-71) lies on the line CD.

Step-by-step explanation:

the x-intercept of CD is[ A(3,0) B(18/5,0) C(9,0) D(45/2,0) ] . Point [ A(-52,117) B(-20,57) C(32,-71) D(-54,-128) ] lies on CD.

Given :

CD is perpendicular bisector of AB.

The coordinates of point A are (-3, 2) and the coordinates of point B are (7, 6).

C is the midpoint of AB.

C=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})=(\frac{7-3}{2},\frac{2+6}{2})=(2,4)

The coordinates of C are (2,4).

Line AB has a slope of:m_1=\frac{y_2-y_1}{x_2-x_1}=\frac{6-2}{7-(-3)}=\frac{4}{10}=\frac{2}{5}

The product of slopes of two perpendicular lines is -1. Since the line CD is perpendicular to AB, therefore the slope of CD : m_2=-\frac{5}{2}

The point slope form of a line is given by:

y-y_1=m(x-x_1)

The slope of line CD is -\frac{5}{2} and the line passing through the point (2,4), the equation of line CD can be written as:

y-4=-\frac{5}{2}(x-2)\\y=-\frac{5}{2}x+5+4\\y=-\frac{5}{2}x+9       .... (1)

The equation of CD is y=-\frac{5}{2}x+9

In order to find the x-intercept, put y=0.

0=-\frac{5}{2}x+9\\\frac{5}{2}x=9\\x=\frac{18}{5}

Therefore the x-intercept of CD is B(18/5,0).

Put x=-52 in eq(1).

y=-\frac{5}{2}(-52)+9=139

Put x=-20 in eq(1).

y=-\frac{5}{2}(-20)+9=59

Put x=32 in eq(1)

y=-\frac{5}{2}(32)+9=-71

Put x=-54 in eq1).

y=-\frac{5}{2}(-54)+9=144

Thus, only point (32,-71) satisfies the equation of CD. Therefore the point C(32,-71) lies on the line CD.

8 0
3 years ago
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