To find concavity we need to find the second derivative.
Use quotient rule to find f'(x)=4/(x+3)^2
Then use chain rule to find f''(x)=-8/(x+3)^3
To find potential inflection points, we need to find all x values where the second derivative is equal to 0 or is undefined.
Set the numerator and denominator equal to 0 and solve.
(x+3)^3=0
x+3=0
x= -3
Now plug a value less than -3 and greater than -3 into the second derivative to find where the concavity is upward (positive number).
Since f''(-4) is positive, that means that f(x) is concave up on the interval (-infinity, -3).
Answer:
30
Step-by-step explanation:
Answer:
the answer is number two
Step-by-step explanation:
Answer:
No, you will not see the graph.
When x is 0, y is –12, which is outside the viewing window.
Because the function has been reflected, it opens down.
From x = –10 to x =10, the y-values range from –22 to –12.
Step-by-step explanation:
