Answer:
a) 151lb.
b) 6.25 lb
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean
and standard deviation
, a large sample size can be approximated to a normal distribution with mean
and standard deviation
.
In this problem, we have that:

So
a) The expected value of the sample mean of the weights is 151 lb.
(b) What is the standard deviation of the sampling distribution of the sample mean weight?
This is 
Answer:
Step-by-step explanation:
You shift up and down when there is a value at the end of the function outside of the parentheses. Since it is -1, you shift down one.
You shift left and right when there is a value inside the parentheses. Since it is 2, you shift left 2. Remember that you always shift left if the number positive and you shift right when it is negative.
6cm^3 =
6* 0.001dm^3=
6*10^(-3)dm^3=
6*10^(-3)*10^(-3)m^3=
6*10^(-6)m^3
or 0.000006 meters cubed
Answer:
Step-by-step explanation:
11