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2 years ago

X-(2x+3) how to solve and why you change the sign for the +3?

Mathematics

2 answers:

alekssr [168]2 years ago

6 0

Answer:

-x - 3

Step-by-step explanation:

x-(2x + 3)

=> x-1(2x + 3)

=> x - 2x - 3

=> -x - 3

Therefore, this is the solution. Hoped this helped.

$GeniusUser$

Lina20 [59]2 years ago

4 0

Answer:

Step-by-step explanation:

x-(2x+3)

Notice that we can't further simplify the things in the bracket so we should multiply by -1

Technically this is like:

x - 1(2x+3)

-1 times 2x = -2x , -1 times 3 is -3

= x - 2x - 3

= -x - 3

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20 points!! Solve this system of lineal equations.separate the x- and y- values with a comma

Zielflug [23.3K]

Solve the following system:{12 x = 54 - 6 y | (equation 1)-17 x = -6 y - 62 | (equation 2)
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Swap equation 1 with equation 2:{-(17 x) + 6 y = -62 | (equation 1)12 x + 6 y = 54 | (equation 2)
Add 12/17 × (equation 1) to equation 2:{-(17 x) + 6 y = -62 | (equation 1)0 x+(174 y)/17 = 174/17 | (equation 2)
Multiply equation 2 by 17/174:{-(17 x) + 6 y = -62 | (equation 1)0 x+y = 1 | (equation 2)
Subtract 6 × (equation 2) from equation 1:{-(17 x)+0 y = -68 | (equation 1)0 x+y = 1 | (equation 2)
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7 0

3 years ago

Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $10,

Andreyy89

Answer:

1) the planning value for the population standard deviation is 10,000

a) Margin of error E = 500, n = 1536.64 ≈ 1537

b) Margin of error E = 200, n = 9604

c) Margin of error E = 100, n = 38416

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

Step-by-step explanation:

Given the data in the question;

1) Planning Value for the population standard deviation will be;

⇒ ( 50,000 - 10,000 ) / 4

= 40,000 / 4

σ = 10,000

Hence, the planning value for the population standard deviation is 10,000

2) how large a sample should be taken if the desired margin of error is;

we know that, n = [ ( $z_{\alpha /2$ × σ ) / E ]²

given that confidence level = 95%, so $z_{\alpha /2$ = 1.96

Now,

a) Margin of error E = 500

n = [ ( $z_{\alpha /2$ × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 500 ]²

n = [ 19600 / 500 ]²

n = 1536.64 ≈ 1537

b) Margin of error E = 200

n = [ ( $z_{\alpha /2$ × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 200 ]²

n = [ 19600 / 200 ]²

n = 9604

c) Margin of error E = 100

n = [ ( $z_{\alpha /2$ × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 100 ]²

n = [ 19600 / 100 ]²

n = 38416

3) Would you recommend trying to obtain the $100 margin of error?

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

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2 years ago

Triangle ABC has side lengths 12, 16, and 20. Do

aev [14]

Answer:

no they dont form a Pythagorean triple

Step-by-step explanation:

a2 + b2 = c2

4 0

2 years ago

The answer?????????????

Aleksandr-060686 [28]

Hey there!

In a rhombus, opposite angles are congruent. This means that 2y is equal to y+34. Let's set up an equation to solve for y.

2y=y+34

We subtract y from both sides.

y=34

Therefore, y=34°

I hope that this helps! Have a wonderful day!

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3 years ago

30 POINTS!!!!

pshichka [43]

He is at sea level 43.5 i am pretty sure

3 0

3 years ago

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