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3 years ago

HELP ME Please I BEG YOU

Mathematics

1 answer:

sasho [114]3 years ago

7 0

Answer:

Step-by-step explanation:

Michele has 4 times the number of trading cards that Lorenzo has

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The proof that AMNS AQNS is shown.

FrozenT [24]

Answer:

The answer is "MS and QS".

Step-by-step explanation:

Given ΔMNQ is isosceles with base MQ, and NR and MQ bisect each other at S. we have to prove that ΔMNS ≅ ΔQNS.

As NR and MQ bisect each other at S

⇒ segments MS and SQ are therefore congruent by the definition of bisector i.e MS=SQ

In ΔMNS and ΔQNS

MN=QN (∵ MNQ is isosceles triangle)

∠NMS=∠NQS (∵ MNQ is isosceles triangle)

MS=SQ (Given)

By SAS rule, ΔMNS ≅ ΔQNS.

Hence, segments MS and SQ are therefore congruent by the definition of bisector.

The correct option is MS and QS

3 0

2 years ago

An environmental science teacher at a high school with a large population of students wanted to estimate the proportion of stude

AnnZ [28]

Answer:

60 students

Step-by-step explanation:

The confidence interval of a proportion is given by:

$p\pm z*\sqrt{\frac{p*(1-p)}{n} }$

Where 'p' is the proportion of students who responded 'yes', 'z' is the z-score for a 95% confidence interval (which is known to be 1.960), and 'n' is the number of students in the sample.

If the confidence interval is from 0.584 to 0.816, then:

$p=\frac{0.584+0.816}{2}=0.7 \\0.816-0.584=2*(1.96*\sqrt{\frac{p*(1-p)}{n}}) \\0.116=1.96*\sqrt{\frac{0.7*(1-0.7)}{n}}\\n=16.8966^2*(0.7*0.3)\\n=60\ students$

60 students were in the sample.

8 0

3 years ago

When building a house, you have the choice of seven different floor plans, brick or stone exterior and carpet or hardwood floori

Yakvenalex [24]

11 im pretty sure....

4 0

2 years ago

Evaluate the expression

Marrrta [24]

The answer would be 16

11 + (8-3)^2 - 20 = 16

3 0

2 years ago

Hey can you please help me posted picture of question

Ronch [10]

The formulas for conditional probability are:
$P(A\cap B')=P(A)\cdot P(B'|A)$
$P(A\cap B')=P(B')\cdot P(A|B')$ .
Since $P(A\cap B')= \frac{1}{6}$ and $p(B')= \frac{7}{18}$ , you have the equation $\frac{1}{6} = \frac{7}{18} \cdot P(A|B')$ .
Therefore, $P(A|B')= \frac{1}{6} : \frac{7}{18} =\frac{1}{6} \cdot \frac{18}{7} = \frac{3}{7}$ .
Answer: The correct choice is D.

8 0

3 years ago