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andrew-mc [135]
3 years ago
15

A submarine cruises underwater at 20 km/h and on

Mathematics
1 answer:
Darina [25.2K]3 years ago
4 0

Answer:

System of equations:

20x + 30y = 650

x + y = 25

Time underwater = 10 hours

Time at the surface = 15 hours

Step-by-step explanation:

Let x = time underwater at 20 km/h.

Let y = time on the surface at 30 km/h.

speed = distance/time

distance = speed * time

distance underwater: 20x

distance on the surface: 30y

total distance: 650

20x + 30y = 650

total time: x + y

total time: 25

x + y = 25

20x + 30y = 650

x + y = 25

20x + 30y = 650

-20x - 20y = -500

--------------------------------

          10y = 150

              y = 15

x + y = 25

x + 15 = 25

x = 10

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Avani has a loyalty card good for a discount at her local hardware store. The item she wants to buy is priced at $17, before dis
Pachacha [2.7K]

The percentage discount on the item will be equal to 8%.

<h3>What is the percentage?</h3>

The Percentage is defined as representing any number with respect to the 100. It is denoted by the sign %.

Given that:-

  • Price of the item before tax and discount = $17
  • After discount and before tax price is = $15.64

The percentage of the discount will be calculated as:-

Percentage discount = ( 17 - 16.64 ) / ( 17 )

Percentage discount= ( 1.36 ) / ( 17 )

Percentage discount = 0.08 x 100 = 8%

Therefore the percentage discount on the item will be equal to 8%.

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Consider the linear equation 2x - 3y = -12 graph the points
levacccp [35]

The graph of linear equation 2x - 3y = -12 is as shown below.

I this question, we have been given a linear equation 2x - 3y = -12

We need to graph the points.

For x = 1,

2(1) - 3y = -12

2 - 3y = -12

-3y = -14

y = 14/3

For x = 0,

2(0) - 3y = -12

y = (-12)/(-3)

y = 4

For x = -1,

2(-1) - 3y = -12

-3y = -12 + 2

y = (-10) / (-3)

y = 10/3

So, we get coordinates (1, 14/3), (0, 4) and (-1, 10/3)

Now we plot these points.

The graph of linear equation 2x - 3y = -12 is as shown below.

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11 months ago
En la tienda de mascotas "Animalo-T", se desea elevar un elefante de 2,900 kg utilizando una elevadora hidráulica de plato grand
Korvikt [17]

Answer:

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

Step-by-step explanation:

Por el Principio de Pascal se conoce que el esfuerzo experimentado por el elefante es igual a la presión ejercida por el plato pequeño. Es decir:

\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}} (1)

Donde:

F_{1} - Fuerza experimentada por el elefante, medida en newtons.

F_{2} - Fuerza aplicada sobre el plato pequeño, medida en newtons.

A_{1} - Área del plato grande, medida en metros cuadrados.

A_{2} - Área del plato pequeño, medida en metros cuadrados.

La fuerza aplicada sobre el plato pequeño es:

F_{2} = \left(\frac{A_{2}}{A_{1}} \right)\cdot F_{1}

La fuerza experimentada por el elefante es su propio peso. Por otra parte, el área del plato es directamente proporcional al cuadrado de su diámetro. Es decir:

F_{2} = \left(\frac{D_{2}}{D_{1}} \right)^{2}\cdot m\cdot g (2)

Donde:

D_{1} - Diámetro del plato grande, medido en centímetros.

D_{2} - Diámetro del plato pequeño, medido en centímetros.

m - Masa del elefante, medida en kilogramos.

g - Aceleración gravitacional, medida en metros por segundo cuadrado.

Si sabemos que D_{1} = 0.75\,m, D_{2} = 0.13\,m, m = 2900\,kg y g = 9.807\,\frac{m}{s^{2}}, entonces la fuerza a aplicar al émbolo pequeño es:

F_{2} = \left(\frac{0.13\,m}{0.75\,m} \right)^{2}\cdot (2900\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

F_{2} = 854.473\,N

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

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