The answer is D. My dad taught me an easy way to solve those kind of problems.You need to do (60×20)÷100. And since 60 and 20 both have a zero and 100 has 2 zeros, u can cross out all the zeros and just do 6×2 and divide that by 1 and so 20% of 60 is 12. Hope this helped :)
Answer:
Pretend that x and y represents the 2 numbers that we need to find.
According to the information, we know that:
x + y = 21
6x = y
Replace y in the first equation with 6x (because they are equal to each other according to the second equation):
x + y = 21
x + 6x = 21
7x = 21
x = 21/7 = 3
Now have two ways to find y, both will give us the same result:
3 + y = 21 ⇔ y = 21 - 3 = 18
6 · 3 = y ⇔ y = 18
So the numbers that we need to find are 3 and 18.
I think it is 0 because it is in the odd and even
Answer: Perpendicular because the second line has a 2/3 slope and starts at 4.
Answer:
And we can find the nnumber of deviations from the mean for each limit given:
![z_1 = \frac{17-32}{5} = -3](https://tex.z-dn.net/?f=%20z_1%20%3D%20%5Cfrac%7B17-32%7D%7B5%7D%20%3D%20-3)
![z_2= \frac{47-32}{5} = 3](https://tex.z-dn.net/?f=%20z_2%3D%20%5Cfrac%7B47-32%7D%7B5%7D%20%3D%203)
So we are 3 deviation from the mean and using the empirical rule we know that within 3 deviations from the mean we have 99.7% of the values
Step-by-step explanation:
Let X the random variable that represent the amount of time it takes him to arrive, and for this case we know the distribution for X is given by:
Where
and
We want to find this probability:
And we can use the z score formula given by:
And we can find the nnumber of deviations from the mean for each limit given:
![z_1 = \frac{17-32}{5} = -3](https://tex.z-dn.net/?f=%20z_1%20%3D%20%5Cfrac%7B17-32%7D%7B5%7D%20%3D%20-3)
![z_2= \frac{47-32}{5} = 3](https://tex.z-dn.net/?f=%20z_2%3D%20%5Cfrac%7B47-32%7D%7B5%7D%20%3D%203)
So we are 3 deviation from the mean and using the empirical rule we know that within 3 deviations from the mean we have 99.7% of the values