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timurjin [86]
3 years ago
10

WILL GIVE BRAINLIEST ANSWER! A circular flower bed is 21 m in diameter and has a circular sidewalk around it that is 33m wide. F

ind the area of the sidewalk in square meters. Use 3.14 for piπ.
Mathematics
1 answer:
Alina [70]3 years ago
5 0

Answer:

The area of the sidewalk is 144.44 m².

The 2-m wide walk adds 4 m to the diameter, making it 21+4=25.

Since the radius is half the diameter, r = 25/2 = 12.5.

The area of the entire bed with walkway is 3.14(12.5)² = 490.625 m².

The diameter of the bed is 21, so the radius is 21/2 = 10.5.

The area of just the flower bed is 3.14(10.5)² = 346.185.

The difference between the two is 490.625-346.185 = 144.44 m².  This is the area of the walkway.

<em>Have a Great Day!</em>

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Answer:

Step-by-step explanation:

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A baby weighed 7.25 lb at birth at the end of 8 months , the baby weighed 2 1/2 times its birth weight. how many pounds did the
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Simply multiply the baby's original weight, which is 7.25 lbs, by 2.5

7.25lbs x 2.5 = 18.125 lbs

The baby weighted 18.125 pounds at the end of 8 months.

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Jabba
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At 6 a.m. the temperature was -9oF. By 11 a.m., the temperature had increased 34oF. What was the temperature at 11 a.m.?
lesantik [10]

The resulting temperature was 25oF.

7 0
2 years ago
100 POINTSSS! ASAP ANSWEERR PLS
Margarita [4]

PART A

Given:

f(x) = 0.69(1.03)x

To find:

If the price of the product is increasing or decreasing and by what percentage

Steps:

we know the formula to find the price of Product A per year, so

f(1) = 0.69 * 1.03 * 1

Price = $0.7107

f(2) = 0.69 * 1.03 * 2

Price = $1.4214

Here the Price of Product after 2 years is greater than the price of Product after one year. So the price of the product A is increasing.

Now to find percentage increase,

Percentage increase = \frac{FV-SV}{SV}*100        (FV = final value, SV = starting value)

Percentage increase = \frac{1.4214 - 0.7107}{0.7107}*100

Percentage increase = \frac{0.7107}{0.7107}*100

Percentage increase = 100 %

Therefore, the percentage increase of Product A is 100%

PART B

Given:

Price of product B in 1st year = $10,100

Price of product B in 2nd year = $10,201

Price of product B in 3rd year = $10,303.01

Price of product B in 4th year = $10,406.04

To find:

Which product recorded a greater percentage change over the previous year

Steps:

We need to find the percentage change of Product B and Product A of each year. We know that the percentage change of product A is 100 % for each year, so we only need to calculate for product B

PC of product B from 1st to 2nd year = \frac{10,201-10,100}{10,100}*100

                                                             = \frac{101}{10,100}*100

                                                             = 0.01 * 100

                                                             = 1 %

PC of product B from 2nd to 3rd year = \frac{10,303.01-10,201}{10,201} *100

                                                              = 1%

PC of product B from 3rd to 4th year =\frac{10,406.04-10,303.01}{10,303.01}*100

                                                              ≈ 1%

So, percentage change of product B is 1% per year

Therefore, Product A has greater percentage change

Happy to help :)

If u need more help, feel free to ask

6 0
3 years ago
Plz right answer=brainlyest
brilliants [131]

Answer:

B—283 cm^2

Step-by-step explanation:

SA=πr^2 + πrl

r=5

l=13

SA=π5^2 + π5*13

SA=π25 + π65

SA=78.5398 + 204.2035

SA=282.7433

SA=283=B

3 0
2 years ago
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