Which of the following is a true statement?
2 answers:
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Answer: The probability that the two children have the disease is 1/16 or 6,25%
Explanation: If the disease only occurs in homozygous individuals and the parents have the trait but not the disease that means is a recesive allele and the parents are heterozygous for this trait.
According to proportions stablished by Mendel, when there is a cross between 2 heterozygous (Ss x Ss) indivdials the probability to obtain a homozygous recesive (ss) descendant is 25% or 1/4 as shown in punnet square below:
Taking into account that the condition of the first kid does not imply the condition for the second, it should be analyzed as 2 independent events.
1. First kid has 1/4 of probability have the dissease as shown in punnet square
2. For a second birth, child has the 25% chance to have the disease
The probability that both events to happen is the product of each event probabilty:
p = 1/4 * 1/4 = 1/16 or 6,25%
Answer:
c. the abyssal plain contains the most biological diversity and the majority of all sea life because it is the ocean bed.
