R(x) = 60x - 0.2x^2
The revenue is maximum when the derivative of R(x) = 0.
dR(x)/dx = 60 - 0.4x = 0
0.4x = 60
x = 60/0.4 = 150
Therefore, maximum revenue is 60(150) - 0.2(150)^2 = 9000 - 4500 = $4,500
Maximum revenue is $4,500 and the number of units is 150 units
The answer is 4. A function cannot have the same x value twice- 1 has two (2), 2 has all (1), 3 has two (-3), so 4 is the only answer.
Answer: x = -2
Step-by-step explanation:
-x + 4x = x - 4
=> 3x = x - 4
=> 3x - x = -4
=> 2x = -4
=> x = -2
6:57 + 47 = 7: 44
or 6:10
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N + 9 = 12 means N is a number which, when added to 9, must give the answer 12. So N can only be the number 3 because only 3 + 9 is equal to 12.
9) (-12) – 3 5-15. 10) (-2) – 5. = -7. 11) (-9)–1 = -10. 12) 3-1. = 2. 13) 10- (-3) = 13 ... n-4 = 22. 9) the product of c and 10 is 24. 10) the sum of a number and 7 is 44 ... 17) (-5)-(-9) . ” (+8)+6-7. 18 (-26) – (-5) -7. 18) (-3). (-1). 24. 19) ī. ” (-2). 3 -2. -3.
