Find the slope and y intercept<br><img src="https://tex.z-dn.net/?f=4x%20%2B%203y%20%3D%203" id="TexFormula1" title="4x + 3y = 3

When a truckload of apples arrives at a packing plant, a random sample of 125 apples are selected and examined for bruises and o

valentinak56 [21]

Answer:

You would need to go 1.6 standard errors away from 0.09.

Step-by-step explanation:

We can solve this using the normal distribution, because, by the Central Limit Theorem, the sampling distribution of the sample proportions is approximately normal.

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

89% of the sample proportions.

50 - 89/2 = 5.5th percentile

50 + 89/2 = 94.5th percentile

5.5th percentile

X when Z has a pvalue of 0.055. So X when Z = -1.6.

So 1.6 standard error away from 0.09.

94.5th percentile

X when Z has a pvalue of 0.945. So X when Z = 1.6.

So 1.6 standard error away from 0.09.

You would need to go 1.6 standard errors away from 0.09.

3 0

4 years ago

What is the value of this expression 1/4−3 ? 12 1/12 64 1/64

kompoz [17]

1/4^(-3) = 4^3 = 64.

8 0

3 years ago

A force of 7 lb is required to hold a spring stretched 9 in. beyond its natural length. How much work W is done in stretching it

Ymorist [56]

144 joules is the work W done in stretching it from its natural length to 13 in beyond its natural length

Force F=10 lb

From the hookes Law

$F=kx$

Therefore, calculate k for the spring for

$10=k(\frac{4}{12}) = > k=\frac{120}{4}=30$

Work done in stretching a spring through a length dx is

$dW=F.dx = > dW=kxdx$

For calculating the work done for stretching the spring to x=6in=(6/12)feet beyond the natural length, Integrate over the limits of x=0 to x=1/2

Therefore,

$\int_{0}^{W}dW=\int_{0}^{0.5}kxdx = > W=\frac{1}{2}k[x^2]_{0}^{0.5}=\frac{1}{2}30 \times (0.5)^2=\frac{30}{8}$

That is,

$W=\frac{15}{4} ft-lb\\$

The answer that is given is for stretching the spring to 4 inches.

Mass of 10 m of chain length is 80kg. This implies, Mass per unit meter length of the chain is

$m_{l}=\frac{80}{10}=8kg/m$

Consider a small length dx of the chain at the end point A. Work done in lifting the small length dx over the height of x meters is

$dW=(8g)dx \times x=8gxdx$

Now, integrate over the the value of x from

x=0 when end of the chain A is on the ground

x=6 when end of the chain A reaches 6 m above the ground

That is,

$\int_{0}^{W}dW=\int_{0}^{6}8gxdx=8g [\frac{x^2}{2}]_{0}^{6}=4g(6^2-0^2)$

$W=4g \times 36=144g \ Joules$

Hence,144 joules is the work W done in stretching it from its natural length to 13 in beyond its natural length

Learn more about Integration here brainly.com/question/2263647

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7 0

2 years ago

What is the purpose of multiplying by the conjugate of a complex denominator when finding the quotient of complex numbers?

Viefleur [7K]

Answer:

C: Radicals in the denominators of fractions are considered unsimplified. You need to multiply a fraction by a value that removes radicals or imaginary numbers in the denominator, which is the complex conjugate of the denominator.

Step-by-step explanation:

5 0

3 years ago

Find the area of a parallelogram with base 15 yards and height 21 2/3 yards

SpyIntel [72]

Answer:

325 yards

Step-by-step explanation:

To find the area of a parallelogram, it is base times height.

Therefore, it is 15 times 65/3 which gives you 325.

I changed 21 2/3 to 65/3 so I could put it into the calculator the easiest. They are the same fraction.

4 0

4 years ago