Question

A line passes through the point (-10,9) and has a slope of -1/2 write an equation in slope-intercept form for this line.

Answer 1

Answer:

$y=-\frac{1}{2} x+4$

Step-by-step explanation:

The equation of a straight line in slope intercept form is given by:

y = mx + c;

where y, x are variables, m is the slope of the line and c is the y intercept (that is value of y when x is 0).

The equation of a line passing through point ($x_1,y_1$) with a slope of -1/2 is given by:

$y-y_1=m(x-x_1)$

Given that the line passes through the point (-10,9) and has a slope of -1/2. Hence the equation of the line is:

$y-9=-\frac{1}{2}(x-(-10)) \\\\y-9=-\frac{1}{2} (x+10)\\\\y=-\frac{1}{2} x-5+9\\\\y=-\frac{1}{2} x+4$