Answer:
the ball reaches a height of 64 feet after 2 sec.
The ball is in the air 4 sec.
Step-by-step explanation:
The ball is following the path of a parabola. The maximum height is at the vertex of the parabola.
Let (h, k) be the vertex. h will be the time it takes to reach the maximum height, and k will be that height.
y = 
h = -b/2a = 64/(-2)(-16) = 64/32 = 2
k = -16(2)^2 + 64(2)
-16(4) + 128
- 64 + 128 = 64
V: (2, 64)
So the ball reaches a height of 64 feet after 2 sec.
Let = 0 (0 is the height when the balls hits the ground)
-16t(t - 4) = 0
t = 0 or t = 4
The ball is in the air 4 sec.
Answer:
$3.62
Step-by-step explanation:
i hope this helps :)
Answer: 64f^24
Steps:
(2f^4)^6
=2f^4 * 2f^4 * 2f^4 * 2f^4 * 2f^4 * 2f^4
=64f^24
Where ^4 means to the power of 4 and so on
Answer:
A
Step-by-step explanation:
Answer:
( -∞, 3]
Step-by-step explanation:
Range is all possible y values that the graph covers.
So in this graph the legs extend all the way to y value -∞ (never mind the x value). However, the top is at y=3 and the graph is not extending above that. Hence the range is from -∞ to and including 3.
