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vazorg [7]
2 years ago
5

George wants to rent a car for a road trip with his friends. He checked the rentals with two companies. Company A charges a non-

refundable fee of $50 and then also $150 for each day. Company B charges using the function 50(2+1). Compare the two functions. Which function has a great rate of change?
Mathematics
1 answer:
andre [41]2 years ago
7 0

Answer:

Company A has a greater daily rate

Step-by-step explanation:

Given

Company A

Base\ Charges=\$50

Daily\ Rate = \$150

Company B

f(x) = 50(2x +1)

Required

Determine the company with greater rate

Simplify the expression of company B

f(x) = 50(2x +1)

f(x) = 50 * 2x + 50 * 1

f(x) = 100x + 50

In a linear function:

f(x) = mx + b

m represents the rates.

This implies that the rate of company B is:

Rate =100

and the rate of company A is

Daily\ Rate = \$150

By comparison:

Company A has a greater daily rate

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ANSWER

P-G = 11{w}^{4} - 5 {w}^{2}  {z}^{2}   - 4z^{4}

EXPLANATION

The given polynomials are:

G =  - 3 {w}^{4}  + 2 {w}^{2}  {z}^{2}  + 5z^{4}

and

P = 8 {w}^{4}   - 3{w}^{2}  {z}^{2}  + z^{4}

We want to subtract these two polynomials.

P-G = 8 {w}^{4}   - 3{w}^{2}  {z}^{2}  + z^{4}  - (- 3 {w}^{4}  + 2 {w}^{2}  {z}^{2}  + 5z^{4} )

Expand the right hand side to obtain:

P-G = 8 {w}^{4}   - 3{w}^{2}  {z}^{2}  + z^{4}   + 3 {w}^{4}   -  2 {w}^{2}  {z}^{2}   -  5z^{4}

Group the similar terms:

P-G = 8 {w}^{4}  + 3 {w}^{4}- 3{w}^{2}  {z}^{2} -  2 {w}^{2}  {z}^{2}   -  5z^{4} + z^{4}

Combine the similar terms to get:

P-G = 11{w}^{4} - 5 {w}^{2}  {z}^{2}   - 4z^{4}

7 0
3 years ago
A ferry will safely accommodate 82 tons of passenger cars. Assume that the meanweight of a passenger car is 2 tons with standard
Shalnov [3]

Answer:

The probability that the maximum safe-weight will be exceeded is <u>0.0455 or 4.55%</u>.

Step-by-step explanation:

Given:

Maximum safe-weight of 37 cars = 82 tons

∴ Maximum safe-weight of 1 car (x) = 82 ÷ 37 = 2.22 tons (Unitary method)

Mean weight of 1 car (μ) = 2 tons

Standard deviation of 37 cars = 0.8 tons

So, standard deviation of 1 car is given as:

\sigma=\frac{0.8}{\sqrt{37}}=0.13

Probability that maximum safe-weight is exceeded, P(x > 2.22) = ?

The sample is normally distributed (Assume)

Now, let us determine the z-score of the mean weight.

The z-score is given as:

z=\frac{x-\mu}{\sigma}\\\\z=\frac{2.22-2}{0.13}\\\\z=\frac{0.22}{0.13}=1.69

Now, finding P(x > 2.22) is same as finding P(z > 1.69).

From the z-score table of normal distribution curve, the value of area under the curve for z < 1.69 is 0.9545.

But we need the area under the curve for z > 1.69.

So, we subtract from the total area. Total area is 1 or 100%.

So, P(z > 1.69) = 1 - P(z < 1.69)

P(z>1.69)=1-0.9545=0.0455\ or\ 4.55\%

Therefore, the probability that the maximum safe-weight will be exceeded is 0.0455 or 4.55%.

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alexdok [17]

Answer:

Bob bought 5 Adult tickets and 3 Child

Step-by-step explanation:

5 adult tickets = 50$

3 Child tickets= 9$

50$+9$= 59$

7 0
3 years ago
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