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2 years ago

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These tables of values represent continuous functions. For which function will the y-values be the greatest for very large value

s of x?
PlzzPlease help me bunnies <3
No monkey business plz. Or I will report

1 answer:

dezoksy [38]2 years ago

7 0

It's C.

The value is increasing threefold relative to the previous step.

all other function values increase by a fixed amount and are therefore linear

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In a 30-60-90 right triangle, the shorter leg has a length of 4. What is the length of the longer leg? How would I figure this o

iVinArrow [24]

Answer:

use a^2 +b^2=c^2

Step-by-step explanation:

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3 years ago

On a survey eight students reported how many minutes it takes them to travel to school here are there responses 9, 11, 3, 14, 14

Triss [41]

Hi!

The answer to your question is 9.75 minutes

Here is the math to prove it:

9+11+3+14+14+7+14+6=78

Now you will take 78 and divide it by 8

This is because when finding the mean you add all of the given number together and then divide them by the amount of number added together.

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Thus, your answer is 9.75 minutes

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2 years ago

Muffins are sold in packages of 18 and cost $27 per package. Each of 6 friends gets an equal share of muffins from p packages of

Rina8888 [55]

Answer:

27/18= 1.5

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Step-by-step explanation:

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2 years ago

Let f(x)=−x√3 . What is the average rate of change of f(x) from 8 to 64?

Fed [463]

Average rate of change of the function: $-\sqrt{3}$

Step-by-step explanation:

The average rate of change of a function f(x) can be calculated as:

$r=\frac{f(x_2)-f(x_1)}{x_2-x_1}$

where:

$x_1, x_2$ are the x-values of the interval taken into account to evaluate the rate of change of the function

$f(x_1),f(x_2)$ are the values of the function at those points

In this problem, we have:

$x_1=8\\x_2=64$

The function is $f(x)=-x\sqrt{3}$ , so

$f(x_1)=f(8)=-8\sqrt{3}\\f(x_2)=f(64)=-64\sqrt{3}$

So, the average rate of change in this interval is:

$r=\frac{-64\sqrt{3}-(-8\sqrt{3})}{64-8}=\frac{-56\sqrt{3}}{56}=-\sqrt{3}$

Learn more about rates of change:

brainly.com/question/4152194

brainly.com/question/12941985

#LearnwithBrainly

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3 years ago

A population of geese grow in such a way that each generation is simply 2.2 times the previous generation. There were 3 geese in

lapo4ka [179]

First generation: 3

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Fourth generation: $3\times2.2\times2.2\times2.2=3\times2.2^3$

And so on. The general formula for the $n$ th generation is $3\times2.2^{n-1}$ . So by the 15th generation, you should expect around $3\times2.2^{15-1}\approx186655$ geese.

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3 years ago

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