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sweet-ann [11.9K]
3 years ago
5

Triangle ABC is transformed to triangle A'B'C', as shown below:

Mathematics
2 answers:
Rashid [163]3 years ago
7 0

Answer:

Option D. m

Step-by-step explanation:

we know that

The transformation of the figure is a reflection, so after the transformation  the shape still has the same size, area, angles and line lengths.

the triangles ABC and A'B'C' are congruent

therefore

the corresponding sides and corresponding angles are equal

so

The relationship between the measures of the angles of the two triangles is

m

m

m

nordsb [41]3 years ago
4 0

Answer:

<em>d). = m∠BCA = m∠B'C'A'</em>

Step-by-step explanation:

d). = m∠BCA = m∠B'C'A'

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10.36 less than the product of 42 and x <br> please i need help
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Answer:

so the problem is saying 42x-10.36 so it's just saying take 10.36 away from 42 multiplied by X

Step-by-step explanation:

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3 years ago
Suppose a tank contains 400 gallons of salt water. If pure water flows into the tank at the rate of 7 gallons per minute and the
Strike441 [17]

Answer:

Step-by-step explanation:

This is a differential equation problem most easily solved with an exponential decay equation of the form

y=Ce^{kt}. We know that the initial amount of salt in the tank is 28 pounds, so

C = 28. Now we just need to find k.

The concentration of salt changes as the pure water flows in and the salt water flows out. So the change in concentration, where y is the concentration of salt in the tank, is \frac{dy}{dt}. Thus, the change in the concentration of salt is found in

\frac{dy}{dt}= inflow of salt - outflow of salt

Pure water, what is flowing into the tank, has no salt in it at all; and since we don't know how much salt is leaving (our unknown, basically), the outflow at 3 gal/min is 3 times the amount of salt leaving out of the 400 gallons of salt water at time t:

3(\frac{y}{400})

Therefore,

\frac{dy}{dt}=0-3(\frac{y}{400}) or just

\frac{dy}{dt}=-\frac{3y}{400} and in terms of time,

-\frac{3t}{400}

Thus, our equation is

y=28e^{-\frac{3t}{400} and filling in 16 for the number of minutes in t:

y = 24.834 pounds of salt

6 0
3 years ago
Find all solutions of e^(e^z)=1
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Start by reviewing your knowledge of natural logarithms. If we take the ln of both sides we get e^z=ln(1). Do the same thing again and wheel about the ln(ln(1)). There's going to be complex solutions, Wolfram Alpah gets them but let me know if you figure out how to do it?
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If (−7, m) is on a circle with center c(3, 5) and radius 10, what is the value of m? m = 5 m equals negative five plus two squar
AfilCa [17]

{(x - 3)}^{2}  +  {(y - 5)}^{2}  = 100 \\ 100 +  {(y - 5)}^{2} = 100 \\ y = 5
7 0
3 years ago
A manufacturer produces bearings, but because of variability in the production process, not all of the bearings have the same di
Lena [83]

Answer:

Proportion of all bearings falls in the acceptable range = 0.9973 or 99.73% .

Step-by-step explanation:

We are given that the diameters have a normal distribution with a mean of 1.3 centimeters (cm) and a standard deviation of 0.01 cm i.e.;

Mean, \mu = 1.3 cm            and           Standard deviation, \sigma = 0.01 cm

Also, since distribution is normal;

                 Z = \frac{X -\mu}{\sigma} ~ N(0,1)

Let X = range of diameters

So, P(1.27 < X < 1.33) = P(X < 1.33) - P(X <=1.27)

  P(X < 1.33) = P( \frac{X -\mu}{\sigma} < \frac{1.33 -1.3}{0.01} ) = P(Z < 3) = 0.99865

  P(X <= 1.27) = P( \frac{X -\mu}{\sigma} < \frac{1.27 -1.3}{0.01} ) = P(Z < -3) = 1 - P(Z < 3) = 1 - 0.99865

                                                                                            = 0.00135

 P(1.27 < X < 1.33) = 0.99865 - 0.00135 = 0.9973 .

Therefore, proportion of all bearings that falls in this acceptable range is 99.73% .

7 0
3 years ago
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