I think the graph below is correct.
Answer:
It must be a solution for both to be a solution to this system
Im going to go with B.The intersection point (x,y) of the two lines.
Answer:
B. R/3
Step-by-step explanation:
Answer:
below
Step-by-step explanation:
You've been asked to use specific x-values. Simply replace the x in the equation for each of your x-values then graph.
first equation!!
(x,y)
y=-2x+5
x-value: -2
y=-2(-2)+5
y=4+5
y=9
(-2, 9)
x-value: -1
y=-2(-1)+5
y=2+5
y=7
(-1, 7)
x-value: 0
y=-2(0)+5
y=0+5
(0, 5)
x-value: 1
y=-2(1)+5
y=-2+5
y=3
(1, 3)
x-value: 2
y=-2(2)+5
y=-4+5
y=1
(2, 1)
second equation :)
(x,y)
y=x^2 +2
x-value: -2
y=-2^2 +2
y=4+2
y=6
(-2, 6)
x-value: -1
y=-1^2 +2
y=1+2
y=3
(-1, 3)
x-value: 0
y=0^2 +2
y=0+2
(0, 2)
x-value: 1
y=1^2 +2
y=1+2
y=3
(1, 3)
x-value: 2
y=2^2 +2
y=4+2
y=6
(2, 6)
third equation
(x,y)
y=√2 x+1
x-value: 1
y=√2 1+1
y=1+1
y=2
(1, 2)
x-value: 4
y=√2 4+1
y=2+1
y=3
(4, 3)
x-value: 9
y=√2 9+1
y=3+1
y=4
(9, 4)
x-value: 16
y=√2 16+1
y=4+1
y=5
(16, 5)
x-value: 25
y=√2 25+1
y=5+1
y=6
(25, 6)
fourth (last) equation :-)
(x,y)
y=4/x
x-value: -4
y=4/-4
y=-1
(-4, -1)
x-value: -2
y=4/-2
y=-2
(-2, -2)
x-value: -1
y=4/-1
y=-4
(-1, -4)
x-value: 0
y=4/0
y=0
(0, 0)
x-value: 1
y=4/1
y=4
(1, 4)
x-value: 2
y=4/2
y=2
(2, 2)
x-value: 4
y=4/4
y=1
(4, 1)
