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Ainat [17]
3 years ago
13

A faucet drip 2/3 gallon h2o in 10 hrs. how much h20 drips per day. 1/15,5/18,1 3/5 or 6 2/3 gallons

Mathematics
1 answer:
kkurt [141]3 years ago
5 0

Answer: The amount of h20 dripping per day is 1 3/5 gallons

Step-by-step explanation: If 2/3 gallons drip for 10 hours

then in 24 hours it will be

= 2/3 * 2.4

= 2 * 0.8

= 1.6 gallons

= 16/10 gallons

= 8/5 gallons

= 1 3/5 gallons

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Geometry help please show work due soon !
Thepotemich [5.8K]
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What is y=4x^2-9x+1 in vertex form
Anna11 [10]

Answer:

y = 4 \left(x - \dfrac{9}{8} \right)^2 - \dfrac{65}{16}

Step-by-step explanation:

y = 4x^2 - 9x + 1

You need to complete the square on the right side.

y = (4x^2 - 9x) + 1

y = 4(x^2 - \dfrac{9}{4}x) + 1

y = 4 \left( x^2 - \dfrac{9}{4}x + \left( \dfrac{9}{8} \right)^2 \right) + 1 - 4\left( \dfrac{9}{8} \right)^2

y = 4 \left(x - \dfrac{9}{8} \right)^2 + 1 - 4 \left( \dfrac{81}{64} \right)

y = 4 \left(x - \dfrac{9}{8} \right)^2 + 1 - \dfrac{81}{16}

y = 4 \left(x - \dfrac{9}{8} \right)^2 + \dfrac{16}{16} - \dfrac{81}{16}

y = 4 \left(x - \dfrac{9}{8} \right)^2 - \dfrac{65}{16}

3 0
3 years ago
Translate each phrase into an algebraic inequality:
Nonamiya [84]

Let hours = x

She can work a maximum of 30 hours so x can be any number from 30 or below.

The inequality would be: X <= 30

5 0
2 years ago
Read 2 more answers
We are given a sequence of five non-zero numbers, where the sum of each term and its neighboring terms is 15 or 25. Find the sum
PSYCHO15rus [73]

We have a sequence that meets the given criteria, and with that information, we want to get the sum of all the terms in the sequence.

We will see that the sum tends to infinity.

So we have 5 terms;

A, B, C, D, E.

We know that the sum of each term and its neighboring terms is 15 or 25.

then:

  • A + B + C = 15 or 25
  • B + C + D = 15 or 25
  • C + D + E = 15 or 25

Now, we want to find the sum of all the terms in the sequence (not only the 5 given).

Then let's assume we write the sum of infinite terms as:

a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + ...

Now we group that sum in pairs of 3 consecutive terms, so we get:

(a_1 + a_2 + a_3) + (a_4 + a_5 + a_6) + ...

So we will have a sum of infinite of these, and each one of these is equal to 15 or 25 (both positive numbers). So when we sum that infinite times (even if we always have the smaller number, 15) the sum will tend to be infinite.

Then we have:

(a_1 + a_2 + a_3) + (a_4 + a_5 + a_6) +  ... \to \infty

If you want to learn more, you can read:

brainly.com/question/21885715

3 0
2 years ago
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