Answer:
The speed of the ball in terms of i and j is (15.76 i, 6.37 j)
Step-by-step explanation:
Given;
velocity of the ball, v = 17 mph
angle of inclination, θ = 22⁰
The horizontal component of the velocity is calculated as;
![V_x = Vcos\theta\\\\V_x = 17cos(22)\\\\V_x = 15.76 \ i](https://tex.z-dn.net/?f=V_x%20%3D%20Vcos%5Ctheta%5C%5C%5C%5CV_x%20%3D%2017cos%2822%29%5C%5C%5C%5CV_x%20%3D%2015.76%20%5C%20i)
The vertical component of the velocity is calculated as;
![V_y = Vsin\theta\\\\V_y = 17sin(22)\\\\V_y = 6.37 \ j](https://tex.z-dn.net/?f=V_y%20%3D%20Vsin%5Ctheta%5C%5C%5C%5CV_y%20%3D%2017sin%2822%29%5C%5C%5C%5CV_y%20%3D%206.37%20%5C%20j)
Therefore, the speed of the ball in terms of i and j is (15.76 i, 6.37 j)