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Ratling [72]
4 years ago
9

In the diagram, a building casts a 35-ft shadow and a flagpole casts an 8-ft shadow. If the flagpole is 18 ft tall, how tall is

the building? Round to the nearest tenth.
Mathematics
2 answers:
Flauer [41]4 years ago
8 0
Let me think... it could be around 28%
Burka [1]4 years ago
7 0

i think the answer is 29....don't quat me because im not 100% shore


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If you add​ Natalie's age and​ Fred's age, the result is 42 . If you add​ Fred's age to 4 times​ Natalie's age, the result is 84
SpyIntel [72]
42 x 4 is 168 and 84 x 4 is 336
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Leto [7]
Correct good job that seem correct
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The perimeter of a square must be greater than 102 inches but less than 138 inches. Find the range of possible side lengths that
liberstina [14]

Answer:

s ∈ (25.5,34.5)

''s'' is in inches unit

s ∈ IR

Step-by-step explanation:

We know that the perimeter of a square is P=4s

Where P is the perimeter and s is the length of a side.

We want the perimeter to be greater than 102 inches but less than 138 inches.

We can write :

102 inches < P < 138 inches

If we replace P = 4s in the expression :

102 inches < 4s < 138 inches

Dividing by ''4''

25.5 inches < s < 34.5 inches

If we want the perimeter to be greater than 102 inches but less than 138 inches the length of a side must be greater than 25.5 inches but less than 34.5 inches.

Writing this in interval notation

s ∈ (25.5,34.5)

s ∈ IR

4 0
3 years ago
Write in standard form
ValentinkaMS [17]
34.06 is the the correct way of saying it.
6 0
3 years ago
What is the axis of symmetry and vertex for the function f(x) = 3(x – 2)2 4?
Travka [436]

we know that

The equation of a vertical parabola in vertex form is equal to

y=a(x-h)^{2}+k

where

(h,k) is the vertex

if a > 0 -----> then the parabola open upward (the vertex is a minimum)

if a < 0 -----> then the parabola open downward (the vertex is a maximum)

The axis of symmetry is equal to

x=h

In this problem let's analyze two cases

First case

f(x)=3(x-2)^{2}+4

the vertex is the point (2,4)

a=3

so

3 > 0 -----> then the parabola open upward (the vertex is a minimum)

The axis of symmetry is equal to

x=2

Second case

f(x)=3(x-2)^{2}-4

the vertex is the point (2,-4)

a=3

so

3 > 0 -----> then the parabola open upward (the vertex is a minimum)

The axis of symmetry is equal to

x=2


6 0
3 years ago
Read 2 more answers
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