Given
mean of 406 grams and a standard deviation of 27 grams.
Find
The heaviest 14% of fruits weigh more than how many grams?
Explanation
given
mean = 406 gms
standard deviation = 27 gms
using standard normal table ,
![\begin{gathered} P(Z>z)=14\% \\ 1-P(Zso , [tex]\begin{gathered} x=z\times\sigma+\mu \\ x=1.08\times27+406 \\ x=435.16 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20P%28Z%3Ez%29%3D14%5C%25%20%5C%5C%201-P%28Zso%20%2C%20%5Btex%5D%5Cbegin%7Bgathered%7D%20x%3Dz%5Ctimes%5Csigma%2B%5Cmu%20%5C%5C%20x%3D1.08%5Ctimes27%2B406%20%5C%5C%20x%3D435.16%20%5Cend%7Bgathered%7D)
Final Answer
Therefore , The heaviest 14% of fruits weigh more than 435.16 gms
Answer:
5 is your answer
Step-by-step explanation:
The 
will equal to 5, because 
= 25
Answer: b
Step-by-step explanation:
Answer:
1195.22N.
Step-by-step explanation:
Mass: m =82.6 kg
Velocity: v= 16.4m/sec.
Distance: d = 9.29 metres.
Acceleration = (v²/2d) = (16.4²/18.58) = 14.47m/sec².
Force = (mass x acceleration) = (82.6 x 14.47) = 1195.22N.
The percentage would be 51% but if you want to round it the answer is 50%
