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nordsb [41]
3 years ago
14

Which of these is NOT a method for proving that a quadrilateral is a parallelogram?A.show that one pair of opposite sides is par

allel and the other is not parallel
B.show both pairs of opposite sides are congruent
C.show one pair of opposite sides are parallel AND congruent
D.show both pairs of opposite sides are parallel
Mathematics
1 answer:
Fynjy0 [20]3 years ago
3 0

Answer:

A

Step-by-step explanation:

Show that one pair of opposite sides is parallel and the other is not parallel

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The usher at a wedding asked each of the 80 guests whether they were a friend of the bride or of the groom. Here are the results
Artyom0805 [142]

Answer: P(B|G) = 3/5 = 0.6

the probability that the guest is the friend of bride, P(bride | groom) is 0.6

Complete Question:

The usher at a wedding asked each of the 80 guests whether they werea friend of the bride or of the groom. The results are: 59 for Bride, 50 for Groom, 30 for both. Given that the randomly chosen guest is the friend of groom, what is the probability that the guest is the friend of bride, P (bride | groom)

Step-by-step explanation:

The conditional probability P(B|G), which is the probability that a guest selected at random who is a friend of the groom is a friend of the bride can be written as;

P(B|G) = P(B∩G)/P(G)

P(G) the probability that a guest selected at random is a friend of the groom.

P(G) = number of groom's friends/total number of guests sample

P(G) = 50/80

P(B∩G) = the probability that a guest selected at random is a friend is a friend of both the bride and the groom.

P(B∩G) = number of guests that are friends of both/total number of sample guest

P(B∩G) = 30/80

Therefore,

P(B|G) = (30/80)/(50/80) = 30/50

P(B|G) = 3/5 = 0.6

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3 years ago
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If the total for four late fees were fifty six dollars, then to find the amount for one, we divide the total by the amount of late fees.

So it'll be 56 / 4 which will equal to 14 dollars.
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Solve for the unknown quantity in each proportion.
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Answer:

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Step-by-step explanation:

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▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ { \huge \mathfrak{Answer}}▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪

As we know that :

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so, over here

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plugging the value of i² as -1

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The first one, 1/8, 3/16, and 3/4, are from least to greatest. 
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