check the picture below.
recall that in a rhombus, both diagonals bisect each other, namely cut each other in equal halves and at right-angles, so we end up with 4 right-triangles.
now, the sides in a rhombus are all equal, thus the perimeter is 13+13+13+13.
D over dx (x sin^2(x)) = sin(x) (sin(x) + 2 x cos(x))
First deal withe the numerator 4 x^2
square root of 4 is 2 and square root of x^2 = x
so square root of 4x^2 is 2x
as for the 3y we can write it as √(3y)
so answer is 2x / √(3y)
Answer:
91 ways. So the answer to the problem's question is THIS : in 15*91 = 1365 ways.
Step-by-step explanation:
When you are finding the mode your looking for the number that shows up the most. In this the mode is 58.
