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Phoenix [80]
3 years ago
6

How to find the indicated angle of a triangle

Mathematics
1 answer:
Irina-Kira [14]3 years ago
8 0
If there’s a missing side you subtract the two know angles from 180*. Plug the two angles into the formula a+b+c=180*. i hope this helps :)
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3 years ago
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I need help with this problem
Arada [10]

Answer:

65.56°

Step-by-step explanation:

We know that if we take dot product of two vectors then it is equal to the product of magnitudes of the vectors and cosine of the angle between them

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So, p·q=|p|*|q|*cosA

⇒cosA=\frac{u.v}{|u||v|}

Given u=-8i-3j and v=-8i+8j

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|v|=\sqrt{(-8)^{2}+ (8)^{2}} =11.3137

let A be angle before u and v

therefore, cosA=\frac{u.v}{|u||v|}=\frac{(-8)*(-8)+(-3)*(8)}{8.544*11.3137} =\frac{40}{96.664}

⇒A=arccos(\frac{40}{96.664} )=arccos(0.4138 )=65.56

Therefore angle between u and v is 65.56°

5 0
3 years ago
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faltersainse [42]

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Murljashka [212]

Answer: A : 54

Step-by-step explanation:

1/7 of 280+14

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