Look at this image. If tectonic plates are moving in the direction pictured, what do you think might happen to the Earth's crust
if it is
pulled that way? What land form, or land forms, might be created? Is there anything else that might happen? Explain your thinking.
Plate
Plate
Asthenosphere
this would create
because
Sentence stem: In the image the plates are moving
pulled that way? What land form, or land forms, might be created? Is there anything else that might happen? Explain your thinking.
Plate
Plate
Asthenosphere
this would create
because
Sentence stem: In the image the plates are moving
1 answer:
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Answer : The heat of the reaction is -221.6 kJ
Explanation :
Heat released by the reaction = Heat absorbed by the calorimeter
where,
= heat released by the reaction = ?
= heat absorbed by the calorimeter
= specific heat of calorimeter =
= change in temperature =
Now put all the given values in the above formula, we get:
As,
So,
Thus, the heat of the reaction is -221.6 kJ
1a. The balanced equation for the reaction is:
<h3>3Ca(OH)₂ + 2H₃PO₄ —> Ca₃(PO₄)₂ + 6H₂O </h3>1b. The number of mole of Ca(OH)₂ is 0.0247 mole
1c. The number of mole of H₃PO₄ is 0.0165 mole.
1d. The concentration of H₃PO₄ is 0.432 mol/L
2. The new concentration of the H₃PO₄ solution is 0.0432 mol/L
<h3>1a. The balanced equation for the reaction</h3><u>3</u>Ca(OH)₂ + <u>2</u>H₃PO₄ —> Ca₃(PO₄)₂ + <u>6</u>H₂O
<h3>1b. Determination of the mole of Ca(OH)₂</h3>Volume of Ca(OH)₂ = 71 mL = 71 / 1000 = 0.071 L
Concentration of Ca(OH)₂ = 0.348 mol/L
<h3>Mole of Ca(OH)₂ =? </h3>Mole = Concentration × Volume
Mole = 0.348 × 0.071
<h3>Mole of Ca(OH)₂ = 0.0247 mole </h3><h3>1c. Determination of the mole of H₃PO₄. </h3>3Ca(OH)₂ + 2H₃PO₄ —> Ca₃(PO₄)₂ + 6H₂O
From the balanced equation above,
3 moles of Ca(OH)₂ reacted with 2 moles of H₃PO₄.
Therefore,
0.0247 moles of Ca(OH)₂ will react with = = 0.0165 mole of H₃PO₄.
Thus, the number of mole of H₃PO₄ is 0.0165 mole
<h3>1d. Determination of the concentration of H₃PO₄</h3>Volume of H₃PO₄ = 38.20 mL = 38.20/ 1000 = 0.0382 L
Mole of H₃PO₄ = 0.0165 mole
<h3>Concentration of H₃PO₄ =?</h3>Initial Volume (V₁) = 10 mL
Initial concentration (C₁) = 0.432 mol/L
New volume (V₂) = 100 mL
<h3>New concentration (C₂) =?</h3>The new concentration of the H₃PO₄ solution can be obtained as follow:
<h3>C₁V₁ = C₂V₂</h3>0.432 × 10 = C₂ × 100
4.32 = C₂ × 100
Divide both side by 100
C₂ =
Therefore, the new concentration of the H₃PO₄ solution is 0.0432 mol/L
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