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deff fn [24]
3 years ago
9

Which statement correctly describes measuring with a graduated cylinder?​

Chemistry
1 answer:
snow_tiger [21]3 years ago
6 0

Answer:

what are the options because a graduated cylinder is a science mixing cylinder is a common piece of laboratory equipment used to measure the volume of a liquid

Explanation:

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calculate the number of coulombs of positive charge in 250cm 3 of (neutral) water. (hint: a hydrogen atom contains one proton; a
Sidana [21]

Number of coulombs of positive charge in 250cm^3 water is 1.3×10^7 C

The volume of 250 cm^3 corresponds to a mass of 250 g since the density of water is 1.0 g/cm^3

This mass corresponds to 250/18 = 14 moles since the molar mass of water is 18. There are ten proton (each with charge q = +e) in each molecule of H_{2}O So,

Q = 14NA  q =14(6.02×10^23)(10)(1.60×10^−19C) = 1.3×10^7 C.

Mass is the quantity of matter in a physical body. It is also a measure of the body's inertia, the resistance to acceleration when a net force is applied. An object's mass also determines the strength of its gravitational attraction to other bodies.

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3 0
1 year ago
BALANCING CHEMICAL EQUATIONS WORKSHEET
kherson [118]

Answer:

Put that in y butt ps

Explanation:

4 0
2 years ago
Titanium has an HCP crystal structure, a c/a ratio of 1.669, an atomic weight of 47.87 g/mol, and a density of 4.51 g/cm3. Compu
IrinaK [193]

Answer : The atomic radius for Ti is, 1.45\times 10^{-8}cm

Explanation :

Atomic weight = 47.87 g/mole

Avogadro's number (N_{A})=6.022\times 10^{23} mol^{-1}

First we have to calculate the volume of HCP crystal structure.

Formula used :  

\rho=\frac{Z\times M}{N_{A}\times V} .............(1)

where,

\rho = density  = 4.51g/cm^3

Z = number of atom in unit cell (for HCP = 6)

M = atomic mass  = 47.87 g/mole

(N_{A}) = Avogadro's number  

V = volume of HCP crystal structure = ?

Now put all the values in above formula (1), we get

4.51g/cm^3=\frac{6\times (47.87g/mol)}{(6.022\times 10^{23}mol^{-1}) \times V}

V=1.06\times 10^{-22}cm^3

Now we have to calculate the atomic radius for Ti.

Formula used :

V=6R^2c\sqrt{3}

Given:

c/a ratio = 1.669 that means,  c = 1.669 a

Now put (c = 1.669 a) and (a = 2R) in this formula, we get:

V=6R^2\times (1.669a)\sqrt{3}

V=6R^2\times (1.669\times 2R)\sqrt{3}

V=(1.669)\times (12\sqrt{3})R^3

Now put all the given values in this formula, we get:

1.06\times 10^{-22}cm^3=(1.669)\times (12\sqrt{3})R^3

R=1.45\times 10^{-8}cm

Therefore, the atomic radius for Ti is, 1.45\times 10^{-8}cm

3 0
3 years ago
Which statement is true of magnets
Harrizon [31]

The statement that is true about magnets is ''Similar poles of a magnet repel each other.''

<h3>What are the characteristics of magnet?</h3>

All magnets have both north and south poles. Opposite poles attract each other, whereas the similar poles repel each other. When you rub a piece of iron along a magnet, this force creates a magnetic field.

So we can conclude that The statement that is true about magnets is ''Similar poles of a magnet repel each other.''

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4 0
2 years ago
Please help me please ​
sweet-ann [11.9K]

Explanation:

1 sugar solution =Distillation

2 Iron powder and sand=magnetic separation

3 petrol and diesel= Fractional distillation

4 Camphor and glass powder = Sublimation

7 0
3 years ago
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