39=9x+7-3x+20
Subtract 27 from each side
12=6x
2=x
Now plug in 2 for x to find AB and BC
9x+7= AB
9(2)+7=AB
18+7= AB
25= AB
-3x+20= BC
-3(2)+20= BC
-6+20= BC
14= BC
Answer:
![x = 33](https://tex.z-dn.net/?f=x%20%3D%2033)
Step-by-step explanation:
Given
![Students = 28](https://tex.z-dn.net/?f=Students%20%3D%2028)
![Brownies = 23](https://tex.z-dn.net/?f=Brownies%20%3D%2023)
![Brownies = 2\ per\ student](https://tex.z-dn.net/?f=Brownies%20%3D%202%5C%20per%5C%20student)
Required
Determine the number of brownies left
If:
![Brownies = 2\ per\ student](https://tex.z-dn.net/?f=Brownies%20%3D%202%5C%20per%5C%20student)
and there are 28 students
Then:
![Total\ Brownies = 2 * 28](https://tex.z-dn.net/?f=Total%5C%20Brownies%20%3D%202%20%2A%2028)
![Total\ Brownies = 56](https://tex.z-dn.net/?f=Total%5C%20Brownies%20%3D%2056)
To determine the number of brownies left, we have:
![Total\ Brownies = Brownies\ Made + Brownies\ Left](https://tex.z-dn.net/?f=Total%5C%20Brownies%20%3D%20Brownies%5C%20Made%20%2B%20Brownies%5C%20Left)
![56 = 23 + x](https://tex.z-dn.net/?f=56%20%3D%2023%20%2B%20x)
Reorder
![x + 23 = 56](https://tex.z-dn.net/?f=x%20%2B%2023%20%3D%2056)
Collect Like Terms
![x = 56 - 23](https://tex.z-dn.net/?f=x%20%3D%2056%20-%2023)
![x = 33](https://tex.z-dn.net/?f=x%20%3D%2033)
<em>Hence, there are 33 brownies left</em>
Answer:
0.3
Step-by-step explanation:
Divide the second term (12) with the first term (40), and you'll get 0.3
This is correct because you get the terms in the correct order when multiplying:
(First term: 40. Common ratio: 0.3)
40 x 0.3 = <u>12</u>
<u>12</u> x 0.3<em> </em>= <em>3.6</em>
40, <u>12</u>, <em>3.6</em>
Answer:
Step-by-step explanation: Ok so it is backwerd to pas would be nagitv