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garri49 [273]
2 years ago
7

A teacher keeps track of the number of students that participate at least three times in an optional study session each year. He

models the attendance over the last nine years with this function. n(t) = 3.53t^2 - 33.04t + 117.56 Which graph would most likely be associated with the given model?

Mathematics
2 answers:
Anastasy [175]2 years ago
6 0

Answer:

It is not C got it wrong.

Step-by-step explanation:

aev [14]2 years ago
3 0

Answer:

its B

Step-by-step explanation:

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What is the y-intercept of the line?
sp2606 [1]
The answer is 1 because that's the point on the graph where x meets 0, or (0, 1)
7 0
2 years ago
(NEED HELP WILL MARK BRAINLIEST)
Basile [38]

Answer:

All of the above

Step-by-step explanation:

Also, this is a history, not a maths problem

6 0
3 years ago
Solve<br>0.9(7x + 14) = 1.5 - (x + 2)
Triss [41]

\\ \sf\longmapsto 0.9(7x+14)=1.5-(x+2)

\\ \sf\longmapsto 6.3x+12.6=1.5-x-2

\\ \sf\longmapsto 63x+12.6=-x-0.5

\\ \sf\longmapsto 63x+x=-0.5-12.6

\\ \sf\longmapsto 64x=-13.1

\\ \sf\longmapsto x=\dfrac{-13.1}{64}

\\ \sf\longmapsto x=0.2

7 0
3 years ago
Use Lagrange multipliers to find the dimensions of the box with volume 1728 cm3 that has minimal surface area. (Enter the dimens
Dima020 [189]

Answer:

(x,y,z) = (12,12,12) cm

Step-by-step explanation:

The box is assumed to be a closed box.

The surface area of a box of dimension x, y and z is given by

S = 2xy + 2xz + 2yz

We're to minimize this function subject to the constraint that

xyz = 1728

The constraint can be rewritten as

xyz - 1728 = 0

Using Lagrange multiplier, we then write the equation in Lagrange form

Lagrange function = Function - λ(constraint)

where λ = Lagrange factor, which can be a function of x, y and z

L(x,y,z) = 2xy + 2xz + 2yz - λ(xyz - 1728)

We then take the partial derivatives of the Lagrange function with respect to x, y, z and λ. Because these are turning points, each of the partial derivatives is equal to 0.

(∂L/∂x) = 2y + 2z - λyz = 0

λ = (2y + 2z)/yz = (2/z) + (2/y)

(∂L/∂y) = 2x + 2z - λxz = 0

λ = (2x + 2z)/xz = (2/z) + (2/x)

(∂L/∂z) = 2x + 2y - λxy = 0

λ = (2x + 2y)/xy = (2/y) + (2/x)

(∂L/∂λ) = xyz - 1728 = 0

We can then equate the values of λ from the first 3 partial derivatives and solve for the values of x, y and z

(2/z) + (2/y) = (2/z) + (2/x)

(2/y) = (2/x)

y = x

Also,

(2/z) + (2/x) = (2/y) + (2/x)

(2/z) = (2/y)

z = y

Hence, at the point where the box has minimal area,

x = y = z

Putting these into the constraint equation or the solution of the fourth partial derivative,

xyz - 1728 = 0

x³ = 1728

x = 12 cm

x = y = z = 12 cm.

7 0
2 years ago
PLEASE HELP ASAP!!!<br><br> How to solve the equations below <br><br> |x−2|=x<br> |x+1|=1−x
kumpel [21]

Answer:

x-2=x x=0

No Solution

x+1=1-x

Cancel   1 on both sides

Subtract   −x from both sides

x+x=0

Simplify x +x  to  2x

2x=0

x=0

Check Answer

x+1=1-x

0+1=1-0

1=1-0

1=1

6 0
3 years ago
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