The Reactance of a Capacitor is t<u>he resistance it has when alternating current (A/C) with a specific frequency (f) passes through it. </u>This is measured in ohms (Ω) and its formula is:
(1)
Where:
is the Reactance in ohms (Ω)
is the frequency of the alternating current in Hertz (
)
is the Capacitance of the Capacitor in Farad (
)
In this case we have a 25 mF capacitor with an applied frequency of 400 Hz.
Note 
Well, with the given data we have to solve (1):
Then:
XC=0.0159 Ω This is the Reactance of the Capacitor
1.75 because 42 divided by 4 is 10.5 and 10.5 divided by 6 is 1.75 i might be wrong but i tried
Answer:
3 for the first one 2ed one is 5
Step-by-step explanation:
Answer:
A. 
Step-by-step explanation:
Given:
To find the quotient, we would multiply the first fraction (⅖) by the reciprocal of the second fraction (reciprocal of ¼ = 4).
This, we would have:
Answer:
A. 2000²⁰⁰¹
Step-by-step explanation:
2000(2000²⁰⁰⁰) = 2000²⁰⁰⁰+1 = 2000²⁰⁰¹
