Establish two right triangles, both with the height of the pole, h.
Call x the distance from the pole to one stake. Then the distance from the other stake to the pole is 6 -x.
Apply Pytagora's equation to both triangles.
1) h^2 = 7^2 - x^2
2) h^2 = 8^2 - (6-x)^2
Eaual 1 to 2
7^2 - x^2 = 8^2 - 6^2 +12x -x^2
12x = 7^2 -8^2 +6^2 = 49 -64 + 36 = 21
x = 1.75
Substitue x-value in 1
h^2 = 49 - (1.75)^2 = 45.94
h = sqrt(45.94) = 6.78
Answer: option d.
Irrational, because it is a repeating decimal.
Answer:
x = 3
Step-by-step explanation:
subtract 7 from both sides, then subtract 4x from both sides after
6x +7 = 4x + 13
-7 -7
6x = 4x +6
-4x -4x
2x = 6
divide both sides by 2x
answer x =3
Answer : Multiplying both sides of the equation by 3.
The answer is A. -5 all others are too big