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AveGali [126]
3 years ago
7

On the way to school, if the ratio of walkers to bus riders is 2:7, then the number of bus riders is ________ times the number o

f walkers.
Mathematics
2 answers:
Yakvenalex [24]3 years ago
7 0
It is 3.5 times the number of walkers
jekas [21]3 years ago
7 0
<span>On the way to school, if the ratio of walkers to bus riders is 2:7, then the number of bus riders is 3.5 times the number of walkers, because 7 (bus riders) divided by 2 (walkers; not to be confused with zombies) is equal to 3.5, which is what you would have to multiply the exact number of walkers by to get the number of bus riders. Good luck, have a great day!~ c: </span>
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4 years ago
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vladimir2022 [97]
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8 0
3 years ago
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If 10 friends are going to occupy 10 seats in shuttle on the way to the airport, how many different ways can they arrange themse
Scorpion4ik [409]

3,628,800 ways can they arrange themselves in the shuttle, If 10 friends are going to occupy 10 seats in shuttle on the way to the airport.

Step-by-step explanation:

The given is,

                   10 friends are going to occupy 10 seats in shuttle on the way to the airport  

Step:1

                   No. of friends - 10

                   No.of seats in space shuttle - 10

                   Formula to calculate the no. of ways to arrange,

                                       P_{n} = n!............................(1)

                    Where, n - Positive integer

Step:2

                  From given, n = 10                  

                  Equation (1) becomes,

                                     P_{10} = 10!

                                            = 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1

                                            = 3628800

                                            = 3628800 ways

Result:

                3,628,800 ways can they arrange themselves in the shuttle, If 10 friends are going to occupy 10 seats in shuttle on the way to the airport.

7 0
3 years ago
What is the vertex of y=3x^2+6x+5
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6 0
3 years ago
EXPLAIN THE ERROR A student solves the compound inequality 15&lt; 2x + 5 &lt; 17 and finds the solutions of the compound inequal
exis [7]

Given : Compound inequality 15< 2x + 5 < 17.

Solution:  In order to solve a compound inequality , we need to isolate for a variable in the middle and get rid all numbers from the middle.

Here in the given problem, we have 2x+5 in the middle.

So, we need to get rid 5 first.

5 is added to 2x. The reverse operation of addition is subtraction.

So, we need to subtract 5 from all sides, from 15, from 2x+5 and from 17.

15-5 < 2x + 5-5  < 17 -5.

On simplifying, we get

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Now, we got 2x in middle. We need to get rid 2 from 2x.

2 is being multiplied with x. The reverse operation of multiplication is division.

Dividing by 2, we get

10÷2 < 2x÷2 < 12÷2

5 < x < 6

We got, x is greater than 5 and less than 6.

Therefore, final answer would not be all real numbers but real numbers between 5 and 6.

Please follow the graph on number line for it.


7 0
3 years ago
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