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Stells [14]
3 years ago
7

Help plzzzz second time show work

Mathematics
1 answer:
il63 [147K]3 years ago
3 0
<h2>i think it is 168ft im not sure though</h2>
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Consider the quadratic equation x? = 4x - 5. How many solutions does the equation have? A The equation has one real solution. Th
anzhelika [568]

Answer:

{-1, 5} (two real solutions).

Step-by-step explanation:

On the left side we want x^2, not x?

We need to rewrite x? = 4x - 5 in standard form, that is, as a quadratic with x terms in decreasing powers of x:

x^2 - 4x + 5 = 0

This factors easily to (x - 5)(x + 1) = 0.

We let each factor equal zero (0) separately and solve for x:  

{-1, 5} (two real solutions).

4 0
3 years ago
PLEASE HELP ASAP Hi! Please help me guys!!! This is difficult for me.. :c ~Why might a solution to an inequality not be reasonab
abruzzese [7]

Answer:

When the solution is negative

Step-by-step explanation:

One example, let's say you are buying pens and each pen cost 3 dollars and you cannot spend more than 15 dollars, how many pens can you buy?

The inequality would be 3x < 15, so any negative solution is not reasonable because you cannot buy negative pens. The same goes for most real-world problems dealing with time, money, or distance.  

8 0
3 years ago
Can someone help me in #66
VladimirAG [237]
\bf log_{{  a}}(xy)\implies log_{{  a}}(x)+log_{{  a}}(y)&#10;\\ \quad \\&#10;% Logarithm of rationals&#10;log_{{  a}}\left(  \frac{x}{y}\right)\implies log_{{  a}}(x)-log_{{  a}}(y)&#10;\\ \quad \\&#10;% Logarithm of exponentials&#10;log_{{  a}}\left( x^{{  b}} \right)\implies {{  b}}\cdot  log_{{  a}}(x)\\\\&#10;-------------------------------\\\\&#10;

\bf log_4\left( \cfrac{\sqrt{x^5y^7}}{zw^4} \right)\implies log_4(\sqrt{x^5y^7})-log_4(zw^4)&#10;\\\\\\&#10;log_4\left[(x^5y^7)^{^\frac{1}{2}}\right]-log_4(zw^4)\implies &#10;\cfrac{1}{2}log_4\left[(x^5y^7)\right]-log_4(zw^4)&#10;\\\\\\&#10;\cfrac{1}{2}\left[ log_4(x^5)+log_4(y^7) \right] -[log_4(z)+log_4(w^4)]&#10;\\\\\\&#10;\cfrac{1}{2}log_4(x^5)+\cfrac{1}{2}log_4(y^7)-[log_4(z)+log_4(w^4)]

\bf \cfrac{1}{2}\cdot 5log_4(x)+\cfrac{1}{2}\cdot 7log_4(y)-log_4(z)-4log_4(w)&#10;\\\\\\&#10;\cfrac{5}{2}log_4(x)+\cfrac{7}{2}log_4(y)-log_4(z)-4log_4(w)
6 0
3 years ago
-5/4-(-1/6) help please
tiny-mole [99]
A way to add fractions that always works is to multiply each numerator by the denominator of the other, then express the sum of products over the product of the denominators.
\dfrac{a}{b}+\dfrac{c}{d}=\dfrac{a}{b}\cdot\dfrac{d}{d}+\dfrac{c}{d}\cdot\dfrac{b}{b}\\\\=\dfrac{ad+bc}{bd}

Here, you have
\dfrac{-5}{4}-\dfrac{-1}{6}=\dfrac{-5\cdot6-(-1)\cdot4}{4\cdot6}=\dfrac{-26}{24}\\\\=\dfrac{-13}{12}=-1\frac{1}{12}

The sum is -1 1/12
3 0
3 years ago
1. How many groups of days are in 1 week?
wolverine [178]

Answer:

(14 groups)

14 divided by 7 = 2

Therefore 14 is your answer

Step-by-step explanation:

lol that's all I got

3 0
3 years ago
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