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elena-s [515]
3 years ago
8

I don't know what is true about 3x9? A. It is 3 is more than 9 B. It is 3 is less than 9 C. It is 3 times as much as 9 D. It is

3 times smaller than 9
Mathematics
1 answer:
geniusboy [140]3 years ago
4 0

Answer:

C. It is 3 times as much as 9

Step-by-step explanation:

3 * 9 = 27

Using elimination method;

A. It is 3 is more than 9

3 + 9 ≠ 27

This is incorrect.

B. It is 3 is less than 9

3 - 9 ≠ 27

This is incorrect.

C. It is 3 times as much as 9

3 * 9 = 27

This is the correct option.

D. It is 3 times smaller than 9

9 / 3 ≠ 27

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How do i find the area for number 4?
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<h3>Answer:  41 cm^2</h3>

Explanation:

Form a horizontal line as shown below (see attached image). This forms 2 separate smaller rectangles

  • The bottom rectangle has area of 4*8 = 32 cm^2
  • The top rectangle has area of 3*3 = 9 cm^2

The total area is therefore 32+9 = 41 cm^2

You can say "square cm" or "sq cm" in place of the "cm^2".

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Emma is playing miniature golf. Her ball is 2 feet to the left of the right-hand wall. The hole is 4 feet to the left of the wal
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Answer:

<u></u>

  • <u>She should aim 6 feet down the wall</u>

Explanation:

The diagram attached sketches the situtation.

Since the angle with which the ball hits the wall is the same with which it bounces, angle β is the same for the two shown triangles.

Then, since both are right triangles, then all the angles are congruent and the triangles are similar. Hence, you can equal the ratios of the sides, to make an equation:

  • x/4 = y/2 ⇒ x = 2y

You have other equation:

  • x+ y = 18

Substitute

  • 2y + y = 18
  • 3y = 18
  • y = 18/3
  • y = 6 ← this is the distance down the wall where the ball should hit

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8 0
3 years ago
A laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighings. Scale readings in repeated we
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Answer:

99% confidence interval for the given specimen is [3.4125 , 3.4155].

Step-by-step explanation:

We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.

Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.

Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;

        P.Q. = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = sample mean weighing of specimen = \frac{3.412+3.416+3.414}{3} = 3.414 g

            \sigma = population standard deviation = 0.001 g

            n = sample of specimen = 3

            \mu = population mean

<em>Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).</em>

So, 99% confidence interval for the population​ mean, \mu is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99  {As the critical value of z at 0.5% level

                                                            of significance are -2.5758 & 2.5758}

P(-2.5758 < \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < 2.5758) = 0.99

P( -2.5758 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X - \mu} < 2.5758 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.99

P( \bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.99

<u>99% confidence interval for</u> \mu = [ \bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } } ]

                                             = [ 3.414-2.5758 \times {\frac{0.001}{\sqrt{3} } } , 3.414+2.5758 \times {\frac{0.001}{\sqrt{3} } } ]

                                             = [3.4125 , 3.4155]

Therefore, 99% confidence interval for this specimen is [3.4125 , 3.4155].

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