HURRY PLEASE
2 answers:
You might be interested in
Answer:
(3 square root of 2 , 135°), (-3 square root of 2 , 315°)
Step-by-step explanation:
Hello!
We need to determine two pairs of polar coordinates for the point (3, -3) with 0°≤ θ < 360°.
We know that the polar coordinate system is a two-dimensional coordinate. The two dimensions are:
- The radial coordinate which is often denoted by r.
- The angular coordinate by θ.
So we need to find r and θ. So we know that:
(1)
x = rcos(θ) (2)
x = rsin(θ) (3)
From the statement we know that (x, y) = (3, -3).
Using the equation (1) we find that:
Using the equations (2) and (3) we find that:
3 = rcos(θ)
-3 = rsin(θ)
Solving the system of equations:
θ= -45
Then:
r = 3\sqrt{2}[/tex]
θ= -45 or 315
Notice that there are two feasible angles, they both have a tangent of -1. The X will take the positive value, and Y the negative one.
So, the solution is:
(3 square root of 2 , 135°), (-3 square root of 2 , 315°)
Diameter of a circle = 
Diameter of a circle =
Diameter of a circle = 75 cm
Diameter of a circle =
Diameter of a circle = 75 cm
Answer:
a = 1, b = 3, c = 1, d = 2, e = 6, and f = 8
Step-by-step explanation:
The given exponential functions are;
2ˣ, 3·2ˣ, and
Let f(x) = 2ˣ, h(x) = 3·2ˣ, and g(x) =
From the table for investigating the dilations of exponential function, we have;
a = f(0) = 2⁰ = 1
b = h(0) = 3·2⁰ = 3 × 1 = 3
c = g(0) = = 2⁰ = 1
d = f(1) = 2¹ = 2
e = h(1) = 3·2¹ = 3 × 2 = 6
f = g(1) = = 2³ = 8.