Hello,
![Area= \frac{16}{3}=2*( k*\sqrt{k}- \int\limits^{\sqrt{k}}_{0} {x^2} \, dx )\\\\ \dfrac{8}{3}=k ^\frac{3}{2}- \frac{1}{3}* [x^3]^{\sqrt{^k}}_0\\\\ 2* k ^\frac{3}{2}=8\\\\ k = \sqrt[3]{16}\\ ](https://tex.z-dn.net/?f=Area%3D%20%5Cfrac%7B16%7D%7B3%7D%3D2%2A%28%20k%2A%5Csqrt%7Bk%7D-%20%5Cint%5Climits%5E%7B%5Csqrt%7Bk%7D%7D_%7B0%7D%20%7Bx%5E2%7D%20%5C%2C%20dx%20%29%5C%5C%5C%5C%0A%0A%20%5Cdfrac%7B8%7D%7B3%7D%3Dk%20%5E%5Cfrac%7B3%7D%7B2%7D-%20%5Cfrac%7B1%7D%7B3%7D%2A%20%5Bx%5E3%5D%5E%7B%5Csqrt%7B%5Ek%7D%7D_0%5C%5C%5C%5C%0A2%2A%20k%20%5E%5Cfrac%7B3%7D%7B2%7D%3D8%5C%5C%5C%5C%0A%0Ak%20%3D%20%5Csqrt%5B3%5D%7B16%7D%5C%5C%0A%0A%0A)
What was the cost per kilometer
1 answer:
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Answer: Sue spends travelling 3.5 hours and spends stationary 2.5 hours
Step-by-step explanation:
The attached image shows Sue's distance-time graph, from there we can observe the segments where she is stationary (lines with no slope) and the segments where she is travelling (lines with slope).
<u>Time spent travelling:</u>
From 2 p.m. to 3 p.m. is 1 hour
From 3:30 p.m. to 4 p.m. is 0.5 hour
From 5 p.m. to 6:30 p.m. is 1.5 hours
From 7:30 p.m. to 8 p.m. is 0.5 hour
Total time travelling=1 h+0.5 h+1.5h+0.5h=3.5 h
<u>Time spent stationary:</u>
From 3 p.m. to 3:30 p.m. is 0.5 hour
From 4 p.m. to 5 p.m. is 1 hour
From 6:30 p.m. to 7:30 p.m. is 1 hour
Total time travelling=0.5 h+1 h+1h=2.5 h
