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Amiraneli [1.4K]

3 years ago

5

Un chip tiene un espesor de 0,12 mm y un atomo de cobre mide 0,00000000133 m.¿cuantos atomos se necesita para alinearlos en el e

spesor de un chip de celular uno a continuacion de otro

1 answer:

aleksandr82 [10.1K]3 years ago

7 0

Answer:

El espesor de un chip es de 0.12mm

Y el diámetro de un átomo de cobre, mide aprox:

0.00000000133 m

Queremos saber cuantos átomos deberemos alinear de tal forma que la "cadena" de átomos de cobre mida 0.12mm

Eso es equivalente a ver cuantas veces entra 0.00000000133 m en 0.12mm

Primero, escribamos ambos valores en las mismas unidades, sabiendo que:

1m = 1000mm

Podemos reescribir:

0.00000000133m = 0.00000000133*(1000 mm) = 0.00000133mm

Entonces tenemos que ver cuantas veces entra 0.00000133mm en 0.12mm

Esto sera igual al cociente entre 0.12mm y 0.00000133mm, esto es:

N = (0.12mm)/(0.00000133mm) = 90,225.6

Redondeamos al próximo número entero:

N = 90,226

Esa es la cantidad de átomos que se necesitan.

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Answer:

Step-by-step explanation:

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$degree of freedom = 15- 1=14$

$\text{confidence interval} \alpha = 1- 0.98 = 0.02 \\ \\ \alpha/2 = 0.02/2 = 0.01$

$From \ X^2 \ table}$ $\text{, the critical value} X^2 \text{=0.99 for degree of freedom =14 is given by : 4.660}$

$\text{, the critical value} X^2 \text{=0.01 for degree of freedom =14 is given by : 29.141}$

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$\text{the confidence interval of the standard deviation} \ \sigma \ is:$

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replacing our values:

$\sqrt{\dfrac{(15 -1)0.0937^2}{29.141} } < \sigma$

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2 years ago

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Step-by-step explanation:

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3 years ago

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3 years ago

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Hannah earned $1536 in 8 years on an investment at a 4% annual simple interest rate. How much was Hannah’s investment? $4800 $30

Nonamiya [84]

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<h3>How to calculate simple interest amount if rate of interest is R% annually?</h3>

Suppose that the initial amount of investment is P

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Then, the amount of simple interest is calculated as:

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Putting values in the above formula, we get;

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