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3 years ago

9

I need help with this Show work on each one

1 answer:

Studentka2010 [4]3 years ago

3 0

Answer:

first one is 1

Second is -2/3

You might be interested in

�� How does the value of sine and cosine of complementary angles relate

vlabodo [156]

Cosine is co added onto sine. Basically, cosine is the sine function moved over 90degrees or pi/2 (pi/2 on a unit circle is 90 degrees)

Sin(x)=cos(x+90) <--degrees
Sin(x)=cos(x+pi/2) <--radians

The above two equations for converting them is called a cofunction identity. There's many more identities to convert sines, cosines, tangents, cosecantes, secantes, and cotangents between each other. This is taught to you in PreCalculus.

7 0

3 years ago

Need help with this problem pics below!

Vikki [24]

Answer:

37

Step-by-step explanation:

8 shape = 25

9 shape = 28

10 shape= 21

11 shape = 34

12 shape= 37

is adding by 3

<h2><u><em>hope it helps</em></u></h2><h2 />

3 0

3 years ago

Find the value of x so that the function has the given value.<br> k(x)=7;k(x)=49

geniusboy [140]

Answer:

i don't what you want me to do here...

You gave me the same problem just two different numbers so maybe the answer is 7... idek tho bro

k times x = 7

k times x = 49

Step-by-step explanation:

6 0

3 years ago

Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0

3 years ago

Joshua and his four friends have 1/2 pakage of a crackers. How many pakages of crackers do they have in all

maks197457 [2]

answer:

2.5 or 2 1/2

work:

4(joshuas friends)+1(joshua)=5

5×1/2=5/2

5/2= 2.5

7 0

3 years ago