Answer:
(4x-7)(4x+7)
Step-by-step explanation:
This is called the Difference of Two Squares (DOTS).
These are the conditions that must be met for DOTS to work:
•There must be 2 terms.
•They must be separated by a negative sign.
•Each term must be a perfect square.
First, you have to find 2 square numbers that times together to make 16.
4×4=16
As we want 16x², you just need to make the 4 become 4x:
4x times 4x equals 16x²
Then, find 2 squares that times together to make 49.
7×7=49
You can put the two squares into a bracket with the x variable first, then the number:
(4x-7)(4x+7)
In the brackets, you always put the negative sign in the first one and then the plus sign in the second one.
You can double check your answer by expanding it back out again using FOIL:
F-First
O-Outer
I-Inner
L-Last
Times the First two in the two brackets:
4x times 4x equals 16x²
Times the Outer two:
4x times 7 equals 28x
Times the Inner two:
-7 times 4x equals -28x
Times the Last two:
-7 times 7 equals -49
Form an equation:
16x²+28x-28x-49
The 28x cancel out to leave:
16x²-49
Hope this helps :)
Answer:
It seems that your options aren't correct as the right answer is -5.3333... (recurring)
Step-by-step explanation:
1) 2x + 4 = 20 + 5x (subtract by the smallest unknown)
-2x -2x
2) 4 = 20 + 3x
-20 -20 (now subtract each side by 20 as we want to leave the unknown on one side and another number on the other side.
3) -16 = 3x (Divide each side by 3)
÷3 = ÷3
4) -5.33333... = x
<h3>Now we have found x but if you're unsure you can substitute to see if your answer is correct.</h3><h3>2 x -5.3333 + 4 = -6.6666</h3><h3>20 + 5 x -5.3333= -6.6665</h3><h3>Our answer is correct! (When answers are rounded, it is equal to the same thing).</h3>
$0.50 is the answer. If the bat is $1.00 more than the baseball, you would subtract that from the total cost which is $1.50 so the answer would be $0.50.
Check the picture below.
since in a rhombus the diagonals bisect each other, thus EC = EA.
now, the rhombus is simply 4 congruent triangles, we know the base and height of one of them, thus
![\bf \textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=8\\ h=15 \end{cases}\implies A=\cfrac{1}{2}(8)(15)\implies A=60 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of all 4 triangles}}{4(60)\implies 240}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20triangle%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B1%7D%7B2%7Dbh~~%20%5Cbegin%7Bcases%7D%20b%3D8%5C%5C%20h%3D15%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B1%7D%7B2%7D%288%29%2815%29%5Cimplies%20A%3D60%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20all%204%20triangles%7D%7D%7B4%2860%29%5Cimplies%20240%7D)
