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2 years ago

Katy is older than Alex and Beth. Sarn is

Mathematics

1 answer:

Sholpan [36]2 years ago

8 0

This would be Delores because it goes katy, Delores, Alex, Sam, Beth

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The cost of labor for servicing cars at B&B Automotive is $50 for each whole hour or for any fraction of an hour. There is a

Masja [62]

Answer:

Step-by-step explanation:

We can use the equation of a straight line to model the cost of servicing the car.

let the cost be y and the number of hours be x

and the charge per hour is m

y=mx+c

y=50x+25

given that the time is 3.45 hours it is assumed that the charge is for 4 hours since for a fraction of 0.45 hours we are charged $50

y=50(4)+25

y=200+25

y=$225

4 0

3 years ago

Factor the polynomial completely.<br><br> 9g^2 - 30gh + 25h^2

Bezzdna [24]

Answer:

Step-by-step explanation:

It's a perfect square.

It factors into (3g - 5h)^2

or (3g - 5h)(3g - 5h)

Make sure it is correctly factored.

3g*3g = 9g^2

3g * - 5h = - 15gh

-5h*3g = - 15gh

5h*5h = 25h^2

These four terms add to 9g^2 - 15gh - 15gh + 25h^2 = 9g^2 - 30gh + 25h^2 which is exactly what you started with.

7 0

3 years ago

What is 7082732*8072-121+818=?

amm1812

Answer:

57171813401

Step-by-step explanation:

3 0

3 years ago

Thom worked 20 hours last week at the sporting-goods store and earned

Ilia_Sergeevich [38]

Answer:

He must work additional 8 hours.

Step-by-step explanation:

Because 1550.00/20=7.75

217.00/7.75=28

28-20=8

So,an additional of 8 hours

6 0

3 years ago

(b) dy/dx = (x - y+ 1)^2

Elanso [62]

Substitute $v(x)=x-y(x)+1$ , so that

$\dfrac{\mathrm dv}{\mathrm dx}=1-\dfrac{\mathrm dy}{\mathrm dx}$

Then the resulting ODE in $v(x)$ is separable, with

$1-\dfrac{\mathrm dv}{\mathrm dx}=v^2\implies\dfrac{\mathrm dv}{1-v^2}=\mathrm dx$

On the left, we can split into partial fractions:

$\dfrac12\left(\dfrac1{1-v}+\dfrac1{1+v}\right)\mathrm dv=\mathrm dx$

Integrating both sides gives

$\dfrac{\ln|1-v|+\ln|1+v|}2=x+C$

$\dfrac12\ln|1-v^2|=x+C$

$1-v^2=e^{2x+C}$

$v=\pm\sqrt{1-Ce^{2x}}$

Now solve for $y(x)$ :

$x-y+1=\pm\sqrt{1-Ce^{2x}}$

$\boxed{y=x+1\pm\sqrt{1-Ce^{2x}}}$

3 0

3 years ago