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3 years ago

Please help me! I need help really fast

Mathematics

2 answers:

Alexus [3.1K]3 years ago

6 0

Answer:

Step-by-step explanation:

Jim will finish in 6 days because 300/50=6

So you know that Sam needs to finish the book in at exactly 4 days

300/4= 75 pages per day

maksim [4K]3 years ago

4 0

Answer:

a lot

Step-by-step explanation:

a lot

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Write a formula for a Riemann sum for the function f (x )equals 1089 minus x squared over the interval [0,33].

Mashcka [7]

Answer:

Area of 23958

Step-by-step explanation:

The Riemann sum is just the divide of a area into smaller areas and computing the sum of those areas. It is basically the integral of a function over an interval.

$\int\limits {1089-x^2} \, dx$

over the interval [0,33].

$\int\limits {1089-x^2} \, dx=1089x-(x^3)/3$

evaluate

$=0-1089\cdot{33}-(33^3)/3=35937-11979=23958$

4 0

3 years ago

27x+3=6<br> Whats is x in that problem

Lilit [14]

Answer:

x=1/3

Step-by-step explanation:

You have to isolate the variable, so you must first separate the constants from the variable. Add 3 on both sides to cancel out the minus three and to move it to the other side. Now you have 27x=9. It's pretty simple from there just use your calculator and divide 27x/27 and also 9/27. That leaves you with 1/3

3 0

3 years ago

△MNP ≅ △TUS. Use the picture below to solve for the following: x, y, and m∠N.

Katyanochek1 [597]

Answer:

x = 32

y = 51

m∠N = 14°

Step-by-step explanation:

Given:

ΔMNP ≅ ΔTUS

By the property of similarity,

MN ≅ TU, NP ≅ US and MP ≅ TS

m∠M = m∠T = 142°,

m∠N = m∠U = (2x - 50)°

m∠P = m∠S = 24°

Since, m∠N = [180°- (m∠M + m∠P)]

(2x - 50) = 180 - (142 + 24)

2x - 50 = 14

2x = 64 ⇒ x = 32

Since, NP = US,

2x - y = 13

2(32) - y = 13

64 - y = 13

y = 51

m∠N = 180° - (142 + 24)°

= 14°

3 0

3 years ago

Hey I really need help its a test -3x=48

Alexus [3.1K]

-3x=48 ---> x=-16
5x-1=29 --> x=6
4(x-6)+7=23 --> x=10
3(x-4)+5x=4 --> x=2

4 0

3 years ago

Students in a school were surveyed about their study habits. Forty-two percent of students said they study on weeknights and wee

MA_775_DIABLO [31]

Answer:

0.6 = 60% probability that he or she studies on a weeknight.

Step-by-step explanation:

We solve this question treating these events as Venn probabilities.

I am going to say that:

Probability A: Probability of a student studying on weeknights.

Probability B: Probability of a student studying on weekends.

Forty-two percent of students said they study on weeknights and weekends

This means that $P(A \cap B) = 0.42$

47% said they studied on weekends

This means that $P(B) = 0.47$

65% said they study either on weeknights or weekends.

This is $P(A \cup B) = 0.65$

If you were to pick one student at random, what is the probability that he or she studies on a weeknight?

This is P(A), and the equation used is:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

Considering the values we have:

$0.65 = P(A) + 0.47 - 0.42$

$0.05 + P(A) = 0.65$

$P(A) = 0.6$

0.6 = 60% probability that he or she studies on a weeknight.

8 0

3 years ago