The difference between the sum of all eight positive integral divisors of 66 and the sum of all eight positive integral divisors of 70 is zero.
<h3>How to find the difference between the integral divisors?</h3>
First let's find the integral divisors. We can write 66 as a product of prime numbers as:
66 = 33*2 = 2*3*11
Then the integral divisors of 66 are:
2
3
11
2*3 = 6
2*11 = 22
3*11 = 33
1 (trivially)
66 (trivially)
The sum gives:
2 + 3 + 11 + 6 + 22 +33 + 1 + 66 = 144
For 70 we have:
70 = 7*10 = 2*5*7
Then the integral divisors are:
1
70
2
5
7
2*5 = 10
2*7 = 14
5*7 = 35
The sum gives:
1 + 70 + 2 +5 + 7 + 10 + 14 + 35 = 144
Then the difference between these two sums is:
144 - 144 = 0
If you want to learn more about integral divisors:
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Answer:
Step-by-step explanation:
The reciprocal of 5: 
The negative reciprocal of 5: 
T=(60cos78, 60sin78)
T=(12.47, 58.69)
C=45
d=√((45-12.47)^2+58.69^2)
d≈67.1km
Hey there!
Our function is:
f(x) = 4^x
If we want to have f(3), we simply can plug in 3 to our answer, and evalutate from there:
f(x) = 4^3 =
4*4*4 =
16*4 =
64
We just calculated 4 to the fourth power, which is four times four times four times four. Therefore, 4 of four is equal to 64.
Hope this helps!
Answer:
<h3>
x = 5 units</h3>
Step-by-step explanation:
area of a triangle = 1/2 base * height
where area = 10 units²
height = x units
base = 4
<u>plugin values into the formula:</u>
10 = 1/2 * 4 * x
x =<u> 10 (2) </u>
4
x = 5 units
