What are your answers? And btw kinda cute
Answer:
The motorist's average rate in the morning trip was 50 mph and that for the afternoon trip was 25 mph.
Step-by-step explanation:
Let the motorist's average rate in the afternoon = <em>x</em> mph.
It is given that his average rate in the morning was twice his average rate in the afternoon.
Therefore, his average rate in the morning = 2<em>x</em> mph.
Let <em>t</em> be the time taken for the morning trip.
It is given that he spent 5 hours for driving.
So, the time taken by him for the afternoon trip = 5 - <em>t</em>.
Now, using the formumla, ,
the verbal model for the morning trip is:
<em>xt</em> = 75
The verbal model for the afternoon trip is:
5<em>x</em> - <em>xt</em> = 50
Substituting <em>xt</em> = 75, we get,
5<em>x</em> - 75 = 50
5<em>x</em> = 125
<em>x</em> = 25
2<em>x</em> = 50
Hence, his average rate in the morning trip was 50 mph and that for the afternoon trip was 25 mph.
Isocoleese means that 2 sides and hence 2 angles are same measure
acute means that all 3 angles are less than 90 degrees
We can rule out choice I since acut means less than 90
II is a possibility, but it doesn't best describe it
III. that is true, but it doesn't include the isocileese part
IV. that is true, but doesn't include the acute part
not sure, either III or IV
Answer:
a) Between 74 and 90
b) 81.86% of the scores are between 78 and 90
Step-by-step explanation:
a) According to the Empirical Rule, in a normal distribution, 95% of the data are within 2 standard deviations of the mean. Therefore, the range that 95% of the scores fall in is between 82-4(2)=74 and 82+4(2)=90.
b) The percent of scores that are between 78 and 90 is: normalcdf(lower,upper,μ,σ) = normalcdf(78,90,82,4) = 0.8185946784 ≈ 0.8186, or about 81.86% of the scores.