Could someone help ASAP

Chemistry

1 answer:

aleksandr82 [10.1K]3 years ago

5 0

Answer: B

Explanation: Im thinking it would be B because it sensible that the gas pushes up to grow as the gas increases. but I would go look it up like a video demonstration that might back this statement up. THANK YOU..

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A chemist needs to determine the concentration of a sulfuric acid solution by titration with a standard sodium hydroxide solutio

Zigmanuir [339]

Answer: The concentration of original sulfuric acid solution is 1.62 M

Explanation:

Let the original concentration of sulfuric acid be 'x' M

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated sulfuric acid solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted sulfuric acid solution

We are given:

$M_1=xM\\V_1=25.00mL\\M_2=?M\\V_2=250.0mL$

Putting values in above equation, we get:

$x\times 25.00=M_2\times 250.0\\\\M_2=\frac{x\times 25.0}{250}=\frac{x}{10}$

Now, to calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2SO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=\frac{x}{10}M\\V_1=10.00mL\\n_2=1\\M_2=0.1790M\\V_2=18.07mL$

Putting values in above equation, we get:

$2\times \frac{x}{10}\times 10.00=1\times 0.1790\times 18.07\\\\x=\frac{1\times 0.1790\times 18.07\times 10}{2\times 10.00}=1.62M$

Hence, the concentration of original sulfuric acid solution is 1.62 M

5 0

4 years ago

Yuki888 [10]

Answer:

The electron took two jumps to return to its ground state.

Explanation:

If the electron is in nth state then it first goes to (n-1)th to 2nd state and emits one photon of this energy gap. Then, it goes to ground state and emits another photon of different energy. It can emit $\left \{ {{n-1} \atop {2}} \right.$ types of different photons. Fourth option is incorrect because in that case it emits one photon and absorbs one photon to go back to that state and also both photons are of same energy.