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Step2247 [10]
2 years ago
12

A hot lump of 36.2 g of iron at an initial temperature of 62.0 °C is placed in 50.0 mL of H2O initially at 25.0 °C and allowed t

o reach thermal equilibrium. What is the final temperature of the iron and water given that the specific heat of iron is 0.449 J/(g·°C)? Assume no heat is lost to surroundings.
Chemistry
1 answer:
Viefleur [7K]2 years ago
7 0
Temperature of 62.0 °C is placed in 50.0 mL of H2O initially at 25.0 °C and allowed to reach thermal equilibrium
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Water boils at 100 Degrees Celsius or 212 degrees Fahrenheit

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2 years ago
Given the two reactions H2S(aq)⇌HS−(aq)+H+(aq), K1 = 9.57×10−8, and HS−(aq)⇌S2−(aq)+H+(aq), K2 = 1.46×10−19, what is the equilib
Dvinal [7]

<u>Answer:</u> The value of K_c for the final reaction is 7.16\times 10^{25}

<u>Explanation:</u>

The given chemical equations follows:

<u>Equation 1:</u>  H_2S(aq.)\rightleftharpoons HS^-(aq.)+H^(aq.);K_1

<u>Equation 2:</u>  HS^-(aq.)\rightleftharpoons S^{2-}(aq.)+H^(aq.);K_2

The net equation follows:

S^{2-}(aq.)+2H^+(aq.)\rightleftharpoons H_2S(aq.);K_c

As, the net reaction is the result of the addition of reverse of first equation and the reverse of second equation. So, the equilibrium constant for the net reaction will be the multiplication of inverse of first equilibrium constant and the inverse of second equilibrium constant.

The value of equilibrium constant for net reaction is:

K_c=\frac{1}{K_1}\times \frac{1}{K_2}

We are given:

K_1=9.57\times 10^{-8}

K_2=1.46\times 10^{-19}

Putting values in above equation, we get:

K_c=\frac{1}{(9.57\times 10^{-8})}\times \frac{1}{(1.46\times 10^{-19})}=7.16\times 10^{25}

Hence, the value of K_c for the final reaction is 7.16\times 10^{25}

5 0
3 years ago
Write a balanced equation for the complete combustion of propane, C3H8 . Do not enter phase symbols. Enter the alkane formula as
Anastaziya [24]
Answer:

C3H8 + 5O2 => 3CO2 + 4H2O

Explanation:

Hydrocarbon combustion is the reaction between a hydrocarbon and O2 producing CO2 and water.

C3H8 + O2 => CO2 + H2O

First we balance the C and H.

C3H8 + O2 => 3CO2 + 4H2O

Now we balance O for the answer!

C3H8 + 5O2 => 3CO2 + 4H2O

3 0
2 years ago
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