Answer:
Explanation:
Given data:
Initial pressure P1 = 4 atm
Final pressure P2 = 0.2 atm
Final volume V2= 500 L
Solution:
First of all we will calculate the initial volume of gas.
P1V1 =P2V2
V1 = P2V2 / P1
V1 = 0.2 atm × 500 L / 4 atm
V1 = 25 L
We can see that in given problem as the volume is increases from 25 L to 500 L pressure is goes to decrease from 4 atm to 0.2 atm.
According to the boyle's law, The volume of given amount of gas is inversely proportional to its pressure, at constant temperature.
V∝ 1/p
V = K/P
PV= K
so,
P1V1 = K and P2V2 = K
or
P1V1 =P2V2
1 mole ----------- 22.4 L ( at STP )
3.5 mols --------- ?
V = 3.5 x 22.4 / 1
V = 78.4 L
hope this helps!
Explanation:
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