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Sliva [168]
3 years ago
8

2(x+4)-1=2x+7 How many solutions for x does the following equation have

Mathematics
1 answer:
Alex73 [517]3 years ago
3 0

Awnser ::::::: There are no signs in the problem

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Which is Greater?<br><br> 0.034 or 0.04
Yuki888 [10]
The second option 0.04 is greater

5 0
3 years ago
Read 2 more answers
How to make 2700 and 600 a fraction
devlian [24]
I think I may be missing something ... I don't completely understand your question. 
All you need to make a fraction is two numbers and a bar.  The bar can be either
horizontal or slanty.  Then you write one number on top and the other number on
the bottom, and bada-bing, you have a fraction.

You can make fractions like

             2700 / 600
                 27 / 6         
                   9 / 2           (all 3 of these have the same value)

             600 / 2700
                 6 / 27         
                 2 / 9              (all 3 of these have the same value) 
8 0
3 years ago
How much money should be deposited today in an account that earns 6% compounded monthly so that it will accumulate to $1000000 (
aleksandr82 [10.1K]

Answer:

The principal investment required to get  a total amount of $ 1,000,000.00  from compound interest at a rate of 6% per year  compounded 12 times per year  over 45 years  is $ 67,659.17.

Step-by-step explanation:

Given

  • Accrued Amount A = $1000000
  • Interest rate r = 6% = 0.06
  • Time period t = 45 years
  • Compounded monthly n = 12

To determine:

  • Principle amount P = ?

Using the formula

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

P\:=\frac{A}{\left(1\:+\:\frac{r}{n}\right)^{nt}}

substituting A = 1000000, r =  0.06, t = 45, and n = 12

P\:=\frac{1000000}{\left(1\:+\:\frac{0.06}{12}\right)^{12\cdot 45}}\:

    =\frac{1000000}{1.005^{540}}

P = 67659.17 $

Therefore, the principal investment required to get  a total amount of $ 1,000,000.00  from compound interest at a rate of 6% per year  compounded 12 times per year  over 45 years  is $ 67,659.17.

7 0
3 years ago
Need help<br> Question in the screenshot below<br> NO spam<br> Please show your work
Alja [10]
<h3>Answer:   x = 6</h3>

======================================================

Work Shown:

\log_{4}(x+10)+\log_{4}(x-2)=\log_{4}(64)\\\\\log_{4}\left((x+10)(x-2)\right)=\log_{4}(64)\\\\(x+10)(x-2)=64\\\\x^2-2x+10x-20=64\\\\x^2-2x+10x-20-64=0\\\\

x^2+8x-84=0\\\\(x+14)(x-6)=0\\\\x+14=0 \ \text{ or } \ x-6=0\\\\x=-14 \ \text{ or } \ x=6\\\\

Those are the possible solutions, but plugging x = -14 back into the original equation will lead to an error. So we rule x = -14 out

x = 6 works as a solution however

3 0
3 years ago
Plzz help will give Brainlest!!
Trava [24]
The second option would be parallel
5 0
3 years ago
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