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3 years ago

How to make 2700 and 600 a fraction

1 answer:

8 0

I think I may be missing something ... I don't completely understand your question.
All you need to make a fraction is two numbers and a bar. The bar can be either
horizontal or slanty. Then you write one number on top and the other number on
the bottom, and bada-bing, you have a fraction.

You can make fractions like

   2700 / 600
   27 / 6
   9 / 2    (all 3 of these have the same value)

   600 / 2700
   6 / 27
   2 / 9 (all 3 of these have the same value)

You might be interested in

Someone please help me

MariettaO [177]

Step-by-step explanation:

$\frac{4}{7}x \: + \: \frac{5}{14}x \: = 39$

$\frac{8}{14}x \: + \: \frac{5}{14}x \: = 39$

$\frac{13}{14}x \: = 39$

x = $\frac{\cancel{39} \times 14}{\cancel{13}}$

x = 3 × 14

x = 42

So, the solution of x is 42

#CMIIW

5 0

4 years ago

Pls help i am in k12 i will mark the brainlyest

olga55 [171]

Step-by-step explanation:

hi I'm in K12 too and this looks like a tga

5 0

3 years ago

A researcher is interested in finding a 95% confidence interval for the mean number minutes students are concentrating on their

Sever21 [200]

Answer:

A. Normal

B. Between 40.08 minutes and 43.92 minutes.

C. About 95 percent of these confidence intervals will contain the true population mean number of minutes of concentration and about 5 percent will not contain the true population mean number of minutes of concentration.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

x% confidence interval:

A confidence interval is built from a sample, has bounds a and b, and has a confidence level of x%. It means that we are x% confident that the population mean is between a and b.

Question A:

By the Central Limit Theorem, a normal distribution.

Question B:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.025 = 0.975$ , so Z = 1.96.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.96\frac{12}{\sqrt{150}} = 1.92$

The lower end of the interval is the sample mean subtracted by M. So it is 42 - 1.92 = 40.08 minutes

The upper end of the interval is the sample mean added to M. So it is 42 + 1.92 = 43.92 minutes

Between 40.08 minutes and 43.92 minutes.

Question C:

x% confidence interval -> x% will contain the true population mean, (100-x)% wont.

So, 95% confidence interval:

About 95 percent of these confidence intervals will contain the true population mean number of minutes of concentration and about 5 percent will not contain the true population mean number of minutes of concentration.

3 0

3 years ago

!! HELP IM IN 7TH GRADE AND M LEARNING 9TH AND 8TH GRADE MATH!!

STALIN [3.7K]

Answer:

The vertex forms an acute angle.

5 0

3 years ago

Ms. Miller wants to give each of her students 1/4 of a pound of modeling clay. She has 26 students. How many pounds of modeling

photoshop1234 [79]

26 * 1/4 =6.5

The answer would be B.

8 0

3 years ago