Answer: ABCD is a quadrilateral
To prove : ∠AOB=
2
1
(∠C+∠D)
AO and BO is bisector of A and B
∠1=∠2∠3=∠4...(1)
∠A+∠B+∠C+∠D=360
(Angle sum property)
2
1
(∠A+∠B+∠C+∠D)=180...(2)
In △AOB
∠1+∠3+∠5=
2
1
(∠A+∠B+∠C+∠D)
∠1+∠3+∠5=∠1+∠3+
2
1
(∠C+∠D)
∠AOB=
2
1
(∠C+∠D)
Explanation: In a quadrilateral ABCD. AO and BO are bisectors of angle A and angle B respectively. Prove that ∠AOB=
2
1
{∠C+∠D}.
Answer:
It would be D
ƒ(x) = 20,000 * (0.93) ^ x
Where ^x means to the power of x
Step-by-step explanation:
Answer:
The surface area of the rectangular pyramid is 
Step-by-step explanation:
we know that
The surface area of the rectangular prism is equal to the area of the rectangular base plus the area of the four triangular faces
so
![SA=(8)(5)+2[14.75]+2[\frac{1}{2}(8)(5)]](https://tex.z-dn.net/?f=SA%3D%288%29%285%29%2B2%5B14.75%5D%2B2%5B%5Cfrac%7B1%7D%7B2%7D%288%29%285%29%5D)
Answer:
When 
and 
:
Step-by-step explanation:
-8ab can be seen as -8×a×b. Insert the given values:
Simplify multiplication from left to right:
Insert and solve:
:Done
I believe the the correct answer would be yes. Two lines can be drawn from a point that is not collinear with a certain line that will meet the line at a right angle or 90 degree angle and at an angle of 45 degrees. We can freely draw any line that would pass through a given point and would cross a given line at any direction giving us different angles and this would include a 90 and 45 degree angle.
