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photoshop1234 [79]
3 years ago
6

PLEASE HELPP! I GOT IT WRONG!

Mathematics
2 answers:
Stels [109]3 years ago
7 0
U good now or is there another one?
Leokris [45]3 years ago
6 0
Don’t worry! You just overthought it! I always do that. Just do 37.80-35=2.80

The answer is 2.80
Have a great day!
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Step-by-step explanation:

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Solution :

It is given that :

$\alpha$ lies in the first quadrant.

And $\beta$ lies in the fourth quadrant.

Since, $\sin \alpha = \frac{5}{13}$     and $\cos \beta = \frac{6}{\sqrt{85}}$    (given)

$\sin \alpha = \frac{5}{13}$  

$\cos \alpha = \sqrt{1-\sin^2 \alpha}$

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Similarly  $\cos \beta = \frac{6}{\sqrt{85}}$

$\sin \beta = \sqrt{1-\cos^2 \beta}$

$\sin \beta = \sqrt{1-\frac{36}{85}}$

     $-\frac{7}{\sqrt{85}}$      (IVth quadrant)

Therefore,

$\cos (\alpha + \beta) = \cos \alpha \cos \beta - \sin \alpha \sin \beta$

                 $=\frac{12}{13}\times \frac{6}{\sqrt{85}}-\frac{5}{13}\times \frac{-7}{\sqrt{85}}$

                $= \frac{107}{13 \sqrt{85}}$

6 0
3 years ago
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Answer:

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divide both sides by 15

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3 years ago
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